C3H8+3O2--->3CO2+8H
Therefore for every 1:3 there are 3 Carbon dioxides that form. That means find the limiting reactant from the two reactants.
5.5g(1mole C3H8/44.03g of C3H8)=0.1249 moled of C3H8 and if for every one C3H8 we can form three CO2. We can assume 0.3747 miles of CO2 will be produced.
15g of O2(1 mole O2/32g of O2)=0.4685moles O2 and if for every three O2 we can produce three CO2 we may assume a 1:1 ratio.
This means C3H8 will be your limiting reactant. Therefore 0.3747 moles of CO2 will be produced.
0.3747 moles of CO2(48.01 g of CO2/1 mole of CO2)= 17.99 grams of CO2
I think the answer is A. breaks rocks apart.
Answer:
The acid will be neutralized overtime
Explanation:
The presence of the pyrites leads to the leaching of large amounts of sulphuric acid, however the basic carbonates neutralizes the acid according to the reaction equation;
CaCO3 + H2SO4 ---> CaSO4 + CO2 + H2O.
This will prevent all the deleterious consequences associated with the leaching of the acid in the abandoned coal mine.
It would be D light dependent reaction, I don’t have much of a explanation but I promise it’s D
I suppose that the answer is A
