The answer is an action potential reaching the end of the axon.
Answer is: pKa for the
monoprotic acid is 5.<span>
Chemical reaction: HA(aq) </span>⇄ A⁻(aq) + H⁺<span>(aq).
c(monoprotic acid) = 0.100 M.
pH = 3.00.
[A</span>⁻] = [H⁺] = 10∧(-3).<span>
[A</span>⁻]
= [H⁺] = 0.001 M; equilibrium concentration.<span>
[HA] = 0.1 M - 0.001 M.
[HA] = 0.099 M.
Ka = [A</span>⁻]·[H⁺] / [HA].<span>
Ka = (0.001 M)² / 0.099 M.
Ka = 0.00001 M = 1.0·10</span>⁻⁵ M.
<span>pKa = -logKa = 4.99.
</span>
Answer:
It was just on a way and scienticts cant really "delete" it from galaxy so they descided accepting it and study it.
Explanation:
Explanation:
Both alcoholic group and carboxylic group are polar in nature.
This is because in carboxylic groups are both hydrogen bond acceptor and hydrogen bond donor. Also there is presence of two electronegative oxygen atoms.
Whereas in alcoholic groups also there is hydrogen bonding and there is one electronegative oxygen atom present.
Hence, it makes carboxylic group more polar.
Thus, we can conclude that 
and 
both are polar in nature.
