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vampirchik [111]

3 years ago

13

What is one way that microorganisms can be beneficial to humans

1 answer:

Anna11 [10]3 years ago

3 0

"Some microbes<span> are used for medicinal production. One of the most important groups of medicines, antibiotics, is produced by fungi and bacteria. The name antibiotics means 'against life'. It is appropriate, because they attack bacteria and other unicellular organisms that are pathogenic for </span>humans<span>."

hope this helps you!</span>

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What is the speed of a 48-kilogram dog running across<br>a lawn with 216 joules of kinetic energy?

pishuonlain [190]

Answer:

3m/s

Explanation:

K.E= (1/2)mv^2

216j= (1/2)48kg • v^2

216J=24kg•v^2

v^2 = (216J)/(24kg)

v^2= 9m^2/s^2

/sqrt{v^2} = /sqrt{9m^2/s^2}

V =3m/s

8 0

3 years ago

Convert -90.0°F to -5.0°c to kelvin

Ratling [72]

-90.0 °F = -67 and 7/9 °C

-90.0 °F also = +205.372 K

-5.0 °C = +23 °F

-5.0 °C also = +268.15 K

4 0

3 years ago

Michelle walked 217 meters in 2 minutes ,55 seconds what is her speed

anyanavicka [17]

Explanation:

55×60=3300

2×60=120

3300+120=3420

speed=distance/time

speed=3420/217

x=15.6ms^-1

8 0

2 years ago

Which energy does a car travelling 30 m/ph as it slows have:

Paladinen [302]

Answer:

c) kinetic energy

Explanation:

6 0

3 years ago

Read 2 more answers

Spring #1 has a force constant of k, and spring #2 has a force constant of 2k. Both springs are attached to the ceiling. Identic

Gre4nikov [31]

Answer:

The ratio of the energy stored by spring #1 to that stored by spring #2 is 2:1

Explanation:

Let the weight that is hooked to two springs be w.

Spring#1:

Force constant= k

let x1 be the extension in spring#1

Therefore by balancing the forces, we get

Spring force= weight

⇒k·x1=w

⇒x1=w/k

Energy stored in a spring is given by $\frac{1}{2}kx^{2}$ where k is the force constant and x is the extension in spring.

Therefore Energy stored in spring#1 is, $\frac{1}{2}k(x1)^{2}$

⇒ $\frac{1}{2}k(\frac{w}{k})^{2}$

⇒ $\frac{w^{2}}{2k}$

Spring #2:

Force constant= 2k

let x2 be the extension in spring#2

Therefore by balancing the forces, we get

Spring force= weight

⇒2k·x2=w

⇒x2=w/2k

Therefore Energy stored in spring#2 is, $\frac{1}{2}2k(x2)^{2}$

⇒ $\frac{1}{2}2k(\frac{w}{2k})^{2}$

⇒ $\frac{w^{2}}{4k}$

∴The ratio of the energy stored by spring #1 to that stored by spring #2 is $\frac{\frac{w^{2}}{2k}}{\frac{w^{2}}{4k}}=$ 2:1

4 0

3 years ago