Differentiate the components of position to get the corresponding components of velocity :
At <em>t</em> = 5.0 s, the particle has velocity
The speed at this time is the magnitude of the velocity :
The direction of motion at this time is the angle that the velocity vector makes with the positive <em>x</em>-axis, such that
1.06 is the <u>maximum</u> refractive index that the liquid may have for the light to be totally reflected.
Only when a light source passes from a denser to a rarer medium can it completely reflect.
When the angle of incidence surpasses a specific critical value, specular reflection occurs in the more highly refractive of the two mediums at their interface, and this reflection is known as total reflection.
sin = μ
/ μ
From the diagram
Angle of incidence = 60°
sin60° ≥ sin = μ
/μ
μ ≤ μ
sin60°
μ ≤ √1.5 × √3/2
= 1.06
Hence, the maximum index that the liquid may have for the light to be totally reflected is 1.06
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