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lakkis [162]
3 years ago
8

The intensity level is 65 db at a distance 5.00 m from a barking dog. What would be a reasonable estimate for the intensity leve

l if two identical dogs very close to each other were barking? You can ignore any interference effects.
Physics
1 answer:
BARSIC [14]3 years ago
7 0

Answer:

68 db

Explanation:

Since now instead of one two dogs are barking simultaneously close to each other, therefore we take n =2.

Ignoring interference effects, the barking of two dogs result in a higher level of intensity which is given by,

β(db)=10×㏒(2)

=3 db

So, a reasonable estimate for the raised Intensity Level is: 65db+3db = 68db

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Read 2 more answers
Ann (mass 50 kg) is standing at the left end of a 15-m-long, 500 kg cart that has frictionless wheels and rolls on a frictionles
ivanzaharov [21]

Answer:

13.5 m

Explanation:

M = Mass of cart = 500 kg

m = Ann's mass = 50 kg

v_m = Velocity of Ann relative to cart = 5 m/s

v_M = Velocity of Cart relative to Ann

As the linear momentum of the system is conserved

Mv_M+mv_m=0\\\Rightarrow v_M=-\frac{mv_m}{M}\\\Rightarrow v_M=-\frac{50\times 5}{500}\\\Rightarrow v_M=-0.5\ m/s

Time taken to reach the right end by Ann

Time=\frac{Distance}{Speed}\\\Rightarrow Time=\frac{15}{5}=3\ s

Distance the cart will move in the 3 seconds

Distance=Speed\times Time\\\Rightarrow Distance=-0.5\times 3=-1.5\ m

The negative sign indicates opposite direction

Movement of Ann will be the sum of the distances

15+(-1.5)=13.5\ m

The net movement of Ann is 13.5 m

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2 years ago
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Paraphin [41]
You have to upload this in the area of mathematicians..!
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