I honestly don’t even know
Answer:- cell potential = -0.19 volts
Solution:- The equation that shows the connection between 
and cell potential, E is written as:
in this equation, n stands for moles of electrons, E stands for cell potential and F stands for faraday constant and it's value is 
.
It asks to calculate the value of E, so let's rearrange the equation:
Let's plug in the values in it:
since, 
Where C stands for coulombs and V stands for volts.
So, 
E = -0.19 V
So, the cell potential is -0.19 volts.
Concentration can be measured in ppm. ppm means parts mer million. In terms of mass , ppm units are mg/kg.
concentration of AgCl solution is the mass of AgCl solute in mg per 1 kg of solution.
mass of AgCl present = 1.2 x 10⁻³ kg = 1.2 mg
mass of solution = 800 g = 0.800 kg
the mass of AgCl in 0.800 kg of solution = 1.2 mg
therefore mass of AgCl in 1 kg of solution = 1.2 mg / 0.800 kg x 1 kg = 1.5 mg
concentration of AgCl is 1.5 mg/kg
since mg/kg = ppm
concentration of AgCl = 1.5 ppm
answer is 1.5 ppm
Answer:
2.5 mL
Explanation:
Step 1: Given data
- Concentration of the active ingredient (C): 5% v/v
- Volume of the medicine (V): 50 mL
Step 2: Calculate the amount of the active ingredient in the medicine
The concentration of the active ingredient is 5% v/v, that is, there are 5 mL of the active ingredient per 100 mL of the medicine. The volume of the active ingredient is 50 mL of the medicine is:
50 mL Med × 5 mL AI/100 mL Med = 2.5 mL AI
Answer:
Sulfur, kill me if I'm wrong
