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Vitek1552 [10]
3 years ago
4

Explain the work-energy theorem, including the direction energy moves and how it relates to positive and negative work.

Physics
2 answers:
ratelena [41]3 years ago
8 0

Answer:

Work is the change in energy brought about by a change in velocity.  

When the velocity of an object increases, the environment has done work on the object and the energy of that object is increased.  

When the velocity of an object decreases, the object has done work on the environment and the energy of the object is decreased.

Explanation:

katrin2010 [14]3 years ago
3 0

Answer:c

Explanation:c

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Which statement best summarizes the central idea of “Applications of Newton’s Laws”?
Shkiper50 [21]

 

Newton's three forces, normal, tension and friction, are present in a surprising number of physical situations

Newton's Laws, that describe the relationship between an obejct and the forces acting upon it, apply in almost every physical situation, from quantum mechanics to electricity.

The correct answer is:

Newton’s laws can explain the forces that occur between objects every day


3 0
4 years ago
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Consider two soap bubbles having radii r1 and r2 (r1 < r2) connected via a valve. What happens if we open the valve?
Alex17521 [72]

Answer:

Explanation:

The radius of the smaller bubble, r1 will decrease and that of the bigger bubble, r2 will increase.

The pressure that is present in the smaller bubble usually is greater than the pressure that exists inside that of the bigger bubble. This then makes air to flow from r1 to r2 thereby making the radius of the smaller bubble r1, to decrease while keeping that of the bigger bubble r2 higher.

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3 years ago
you just saw a magazine ad that shows several people having fun at a football game. They are all wearing a specific shoe brand.
Scilla [17]
The answer for the question is bandwagon. Hope it helped :)

6 0
3 years ago
Calculate the monentun pf 75 kg bicycle and boy who has ghe velocitg of 3m/s
Grace [21]

Explanation:

n=75 kg

v=3m/s

m=n×v

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m= 225n

6 0
3 years ago
Determine the automobile’s braking distance from 90 km/h when it is going up a 5° incline. (Round the final value to one decimal
NeX [460]

Answer:

366 m

Explanation:

u = 90 km/h = 25 m/s,

theta = 5 degree

acceleration, a = g Sin theta = 9.8 x Sin 5 = 0.854 m/s^2

The final velocity os zero and let the braking distance be s.

Use third equation of motion

v^2 = u^2 - 2 a s

0 = 25 x 25 - 2 x 0.854 x s

s = 366 m

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3 years ago
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