1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Volgvan
3 years ago
11

The solubility of acetanilide in hot water (5.5 g/100 ml at 100 C) is not very great, and it has some solubility in cold water (

0.53 g/100 ml at 0 C). What would be the maximum theoretical percent recovery from the crystallization of 4.0 g of acetanilide from 100 ml of water (assuming the solution is chilled to 0 C for filtration). Show your calculations.
Chemistry
2 answers:
sashaice [31]3 years ago
5 0

To answer the problem given:

|0.53−4.0| / 4.0 * 100%

= 3.47 / 4.0 * 100%

= 87%

The maximum theoretical percent recovery from the crystallization of 4.0 g of acetanilide from 100 ml of water is 87%. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

son4ous [18]3 years ago
4 0

Answer:

Maximum theoretical percent recovery of acetanilide is 86.8%

Explanation:

From the given information:

Solubility of acetanilide in 100 ml water at 100 C = 5.5 g

Solubility of acetanilide in 100 ml water at 0 C = 0.53 g

When 4.0 g of acetanilide is dissolved in 100 ml of water, all of it will go into solution. As the solution is cooled to 0 C only 0.53 g of it will dissolve.

Amount of acetanilide undissolved = 4.0 - 0.53 = 3.47 g\\\\Percent\ recovery = \frac{3.47g}{4.00} *100=86.75% (86.8%\ approx)

You might be interested in
What is the correct equilibrium constant
Elza [17]

Answer:[co2][CF4]

[COF2]^2

Explanation:

4 0
3 years ago
Read 2 more answers
a student prepares a dilute solution of sodium hydroxidem, NaOH (aq), starting with 6 M sodium hydroxide. She then titrates a 1.
Serjik [45]

Answer:

M = 0.3077 M

Explanation:

As I said in the comments, you are missing the required volume of the base to react with the KHP. I found this on another site, and the volume it used was 21.84 mL.

Now, KHP is a compound often used to standarize NaOH or KOH solutions. This is because it contains a mole ratio of 1:1 with the base, so it's pretty easy to use and standarize any base.

Now, as we are using an acid base titration, the general expression to use when a acid base titration reach the equivalence point would be:

n₁ = n₂   (1)

This, of course, if the mole ratio is 1:1. In the case of KHP and NaOH it is.

Now, we also know that moles can be expressed like this:

n = M * V   (2)

And according to this, we are given the volume of base and the required mass of KHP. So, if we want to know the concentration of the base, we need to get the moles of the KHP, because in the equivalence point, these moles are the same moles of base.

The reported molar mass of KHP is 204.22 g/mol, so the moles are:

n = 1.372 / 204.22 = 6.72x10⁻³ moles

Now, we will use expression (2) to get the concentration of the diluted base:

n = M * V

M = n / V

M = 6.72x10⁻³ / 0.02184

M NaOH = 0.3077 M

This is the concentration of the dilute solution of NaOH

3 0
3 years ago
A compound is found to contain 37.32 % phosphorus , 16.88 % nitrogen , and 45.79 % fluorine by
Alla [95]

Answer: 1. The empirical formula is PNF_2  

2. The molecular formula is PNF_2

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of P = 37.32 g

Mass of N = 16.88 g

Mass of F = 45.79 g

Step 1 : convert given masses into moles.

Moles of P =\frac{\text{ given mass of P}}{\text{ molar mass of P}}= \frac{37.32g}{31g/mole}=1.20moles

Moles of N =\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{16.88g}{14g/mole}=1.20moles

Moles of F =\frac{\text{ given mass of F}}{\text{ molar mass of F}}= \frac{45.79g}{19g/mole}=2.41moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For P = \frac{1.20}{1.20}=1

For N = \frac{1.20}{1.20}=1

For F =\frac{2.41}{1.20}=2

The ratio of P: N: F= 1: 1: 2  

Hence the empirical formula is PNF_2

The empirical weight of PNF_2= 1(31)+1(14)+2(19)= 82.98 g.

The molecular weight = 82.98 g/mole

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight}}{\text{Equivalent weight}}=\frac{82.98}{82.98}=1

The molecular formula will be=1\times PNF_2=PNF_2

3 0
3 years ago
What would happen to a animal cell if it had n\an lysosome?
pantera1 [17]
Honestly I don't know
4 0
3 years ago
Neon is a noble gas because it is stable non reactive and has ____ valence electrons
lesya692 [45]

Answer:

8 .....................

3 0
3 years ago
Other questions:
  • Carbon obtained from a sample of frozen skin in a glacier is found to have one-half the 14c-to-12c ratio of present-day carbon.
    6·1 answer
  • A 6.00 g sample of calcium sulfide is found to contain 3.33 g of calcium. what is the percent by mass of sulfur in the compound?
    9·1 answer
  • In the reaction
    12·2 answers
  • Which statement describes a change that occurs during a chemical reaction?
    8·1 answer
  • On a cold, cloudy day, the local weather forecaster predicts that a high-pressure system will be moving into the area in the nex
    15·1 answer
  • Which of these would produce a soft sound A (a slow vibration) B (a big vibration) C (a fast vibration) or D (a tiny vibration)
    5·1 answer
  • A gas is collected at 30 Celsius and has a pressure of 200 kPa. What pressure would it exert if the temperature changed to 40 Ce
    14·1 answer
  • In the free radical chlorination of methylcyclopentane, what is the total number of distinct monochlorinated compounds, includin
    6·1 answer
  • Zamir and Talia raced through a maze. Zamir walked 2 m north, 2 m east, 4 m south, 2 m east, 4 m north, 2 m east, 3 m south, 4 m
    13·2 answers
  • How are all atoms of silver alike, but different from atoms of other elements?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!