If the swimmer could cross a 14 km channel maintaining the same average velocity as for the first 50 m in the pool, how long wou
1 answer:
Complete question:
If the swimmer could cross a 14 km channel maintaining the same average velocity as for the first 50 m in the pool, how long would it take?
For the first 50m in the pool, the average velocity was 2.08 m/s
Answer:
It would take for the swimmer approximately 1.87 hours.
Explanation:
If the swimmer maintains the average velocity on the channel, we should find and approximate value of the time it takes to cross the channel with the Galileo’s kinematic equation:
With x the displacement, v the average velocity and t the time, solving for t:
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- initial velocity=u=15m/s
- Final velocity=v=75m/s
- Time=t=5s
Answer:
Explanation:
Two identical bodies are sliding toward each other on a frictionless surface.
Initial speed of body 1, m₁ = 1 m/s
Initial speed of body 2, m₂ = 2 m/s
They collide and stick.
We need to find the speed of the combined mass. Let V is the speed of the combined mass.
Using the conservation of momentum.
We have, m₁ = m₂ = m
So, the speed of the combined mass is .