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CaHeK987 [17]
4 years ago
6

If the swimmer could cross a 14 km channel maintaining the same average velocity as for the first 50 m in the pool, how long wou

ld it take?
Physics
1 answer:
alukav5142 [94]4 years ago
7 0

Complete question:

If the swimmer could cross a 14 km channel maintaining the same average velocity as for the first 50 m in the pool, how long would it take?

For the first 50m in the pool, the average velocity was 2.08 m/s

Answer:

It would take for the swimmer approximately 1.87 hours.

Explanation:

If the swimmer maintains the average velocity on the channel, we should find and approximate value of the time it takes to cross the channel with the Galileo’s kinematic equation:

x=vt

With x the displacement, v the average velocity and t the time, solving for t:

t=\frac{x}{v}=\frac{14000m}{2.08\frac{m}{s}}

t=6730.7 s= 1.87 h

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An energy plant produces an output potential of 1500 kV and serves a city 143 km away. A high-voltage transmission line carries
jekas [21]

Answer:

2123.55 $/hr

Explanation:

Given parameters are:

V_{plant} = 1500 KV

L = 143 km

I = 500 A

\rho = 2.4 \Omega / km

So, we will find the voltage potential provided for the city as:

V_{wire} =IR = I\rho L = 1500*2.4*143 = 514.8 kV

V_{city} = V_{plant}- V_{wire} = 1500-514.8 = 985.2 kV

Then, we will find dissipated power because of the resistive loss on the transmission line as:

P = I^2R = I^2\rho L=500^2*2.4*143 = 8.58*10^7 W

Since the charge of plant is not given for electric energy, let's assume it randomly as x =  \frac{\dollar 0.081}{kW.hr}

Then, we will find the price of energy transmitted to the city as:

Cost = P * x = 8.58*10^7 * 0.081 * 0.001 = 6949.8 $/hr

To calculate money per hour saved by increasing the electric potential of the power plant:

Finally,

I_{new} = P/V_{new} = I/1.2\\P_{new} = I_{new}^2R_{wire}\\Cost = P_{new}/1.44=6949.8/1.44 = 4826.25 $/hr

The amount of money saved per hour = 6949.8 - 6949.8/1.44 = 2123.55 $/hr

Note: For different value of the price of energy, it just can be substituted in the equations above, and proper result can be found accordingly.

3 0
3 years ago
The heliocentric system gained support when Galileo observed that _____.
lianna [129]
Venus goes through phases similar to those of earths moon.
4 0
3 years ago
Find the odd one out radish,potato, beet,carrot.​
romanna [79]

Answer:

Potato is not a root whereas the rest of the four items are forms of root.

Potato is a stem.

So, option B is the odd one out

4 0
3 years ago
A 330-km-long high-voltage transmission line 2.00 cm in diameter carries a steady current of 1,110 A. If the conductor is copper
vodka [1.7K]

Answer:

t = 402 years

Explanation:

To find the number of year that electrons take in crossing the complete transmission line, you first calculate the drift speed of the electrons. Then, you use the following formula for the current in a wire:

I=nqv_dA  (1)

n: number of mobile charge carrier per volume = 8.50*10^28 e/m^3

q: charge of the electron = 1.6*10^-19 C

vd: drift velocity of electron in the metal = ?

A: cross sectional area of the wire = π r^2 = π (0.02m/2)^2 = 3.1415*10^-4 m^2

I: current in the wire = 1110 A

You solve the equation (1) for vd:

v_d=\frac{I}{nqA}=\frac{110A}{(8.50*10^{28}m^{-3})(1.6*10^{-19}C)(3.1415*10^{-4}m^2)}\\\\v_d=2.59*10^{-4}m/s

Next, you calculate the time by using the information about the length of the line transmission:

x=v_dt\\\\x=330km=330000m\\\\t=\frac{x}{v_d}=\frac{330000m}{2.59*10^{-4}m/s}=1,270,184,865s\\\\1,270,184,865s*\frac{1\ year}{3,156,107}=402.45\ years

hence, the electrons will take aproximately 402 years in crossing the line of transmission

6 0
3 years ago
Which element has a magnetic properties​
vodomira [7]

Answer:

Since then only three elements on the periodic table have been found to be ferromagnetic at room temperature - iron (Fe), cobalt (Co), and nickel (Ni). The rare earth element gadolinium (Gd) nearly misses by only 8 degrees Celsius.

Explanation:

3 0
3 years ago
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