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Mila [183]
3 years ago
5

Common car loan duration

Engineering
1 answer:
chubhunter [2.5K]3 years ago
4 0

Answer:

In 2019, the average term length was 69 months for new cars and 65 months for used vehicles. Most car loans are available in 12 month increments, lasting between two and eight years. The most common loan terms are 24, 36, 48, 60, 72, and 84 months, according to Autotrader

Explanation:

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Which of the following identifies a criterion needed to become a civil engineer?
denis23 [38]
I’m pretty sure the answer is B
5 0
4 years ago
Write the definition of a function printLarger, which has two int parameters and returns nothing. The function prints the larger
vredina [299]

Answer:

  1. #include <iostream>
  2. using namespace std;
  3. void printLarger(int a, int b){
  4.    
  5.    if(a > b){
  6.        cout<<a;
  7.    }else{
  8.        cout<<b;
  9.    }
  10. }
  11. int main()
  12. {
  13.    printLarger(4, 5);
  14.    return 0;
  15. }

Explanation:

The solution code is written in C++.

Firstly define a function printLarger that has two parameters, a and b with both of them are integer type (Line 5). In the function, create an if condition to check if a bigger than b, print a to terminal (Line 7-8). Otherwise print b (Line 9-10).

In the main program, test the function by passing 4 and 5 as arguments (Line 16) and we shall get 5 printed.  

7 0
4 years ago
A convergentâdivergent nozzle has an exit area to throat area ratio of 4. It is supplied with air from a large reservoir in whic
ryzh [129]

Answer:

Angle of discharge make at the edge of tube=64.9 degrees.

5 0
3 years ago
Mathew is manufacturing overhead transmission wires for the working of electric trains. On what does the insulation of these wir
elena-14-01-66 [18.8K]

Answer:

B

Explanation:

4 0
3 years ago
Find the percent change in cutting speed required to give an 80% reduction in tool life when the value of n is 0.12.
vaieri [72.5K]

Answer:21.3%

Explanation:

Given

80 % reduction in tool life

According to Taylor's tool life

VT^n=c

where V is cutting velocity

T=tool life of tool

80 % tool life reduction i.e. New tool Life is 0.2T

Thus

VT^{0.12}=V'\left ( 0.2T\right )^{0.12}

V'=\frac{V}{0.2^{0.12}}

V'=\frac{V}{0.824}=1.213V

Thus a change of 21.3 %(increment) is required to reduce tool life by 80%

6 0
3 years ago
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