Answer:
53.18 gL⁻¹
Explanation:
Given that:
------equation (1)
where;
Formation Constant
However, the Dissociation of yields:
⇄
-------------- equation (2)
where;
the Solubility Constant
From equation (1);
--------- equation (3)
From equation (2)
--------- equation (4)
In , the net reaction for
can be illustrated as:
⇄
The equilibrium constant (K) can be written as :
If we multiply both the numerator and the denominator with ; we have:
≅
Now; we can re-write our equilibrium constant again as:
By finding the square of both sides, we have
In gL⁻¹; the solubility of in 0.76 M
solution will be:
= 53.18 gL⁻¹