mass (m) = ? , volume = 18.0 ml , density = 1.42 g/ml .
![density = \frac{mass}{volume} \\ \\ d = \frac{m}{v} \\ \\ mass = density \times volume \\ \\ m = d \times v \\ \\ m = 18 \: ml \times \: 1.42 \: \frac{g}{ml} \\ \\ m = 25.56 \: g](https://tex.z-dn.net/?f=density%20%3D%20%20%5Cfrac%7Bmass%7D%7Bvolume%7D%20%20%5C%5C%20%20%5C%5C%20d%20%3D%20%20%5Cfrac%7Bm%7D%7Bv%7D%20%20%5C%5C%20%20%5C%5C%20mass%20%3D%20density%20%5Ctimes%20volume%20%5C%5C%20%20%5C%5C%20m%20%3D%20d%20%5Ctimes%20v%20%5C%5C%20%20%5C%5C%20m%20%3D%2018%20%5C%3A%20ml%20%5Ctimes%20%20%5C%3A%201.42%20%5C%3A%20%20%5Cfrac%7Bg%7D%7Bml%7D%20%20%5C%5C%20%20%5C%5C%20m%20%3D%2025.56%20%5C%3A%20g)
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Answer:this is all i found out
Oxygen is known as a diatomic molecule. Oxygen atom has atomic number as 8 so it has its K shell completely filled with 2 electrons. While it has only 6 electrons in L shell which requires 8 electrons to get inert gas configuration. So oxygen atom shares 2 electrons with another oxygen atom to form a diatomic molecule.
Explanation:
A compound can be treated like an element when balancing chemical equations when : A. when there is no change to the atoms in the compound
If they remain together during the reaction, you can treat a compound as a singe atom.
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Answer:
*2Kl+Pb(NO3)2=PbI2+2KNO3: double replacement.
*2Al+3CuSO4=Al2(SO4)3+3Cu: single replacement.
*C2H5OH+3O2=2CO2+3H2O: combustion.
Explanation:
Hello there!
In this case, according to the required, it turns out necessary for us to recall the five types of reactions, combination, decomposition, single and double replacement and combustion as shown on the attached figure.
In such a way, since the first reaction follows the pattern AB+CD-->AD+CB we infer it is double replacement; the second reaction follows the patter A+BC-->AC+B and therefore it is single replacement; and the last one follows the pattern of combustion reaction due to the presence of CO2 and H2O on the products side.
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