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nexus9112 [7]
4 years ago
12

A true experiment involves the identification and control of variables. What is an example of a scientific investigation that mi

ght not involve a true experiment
Physics
1 answer:
Karolina [17]4 years ago
5 0

Answer:

Explanation:

Since the definition of true experiment has been provided in the question, let's proceed to define some other parameters.

Scientific investigation <u>that might not involve a true experiment is called non-experimental research </u>while the one that involves a true experiment is called experimental research.

Non-experimental researches are usually descriptive in nature. An example of a non-experimental research is the observation and recording of the number and the beak type of birds that visits a park. As seen, this experiment does not have it's variables set out for identification or even control.

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Which of the following is not a
marissa [1.9K]

Answer:

polarization

Explanation:

6 0
3 years ago
A 0.015 kg marble sliding to the right at 22.5 cm/s on a frictionless surface makes an elastic head-on collision with a 0.015 kg
slava [35]

Answer:

Explanation:

mass of first marble m_1=m=0.015\ kg

Initial velocity of the first marble u_1=22.5\ m/s

considering right side as positive

Mass of second marble

m_2=m=0.015\ kg\\u_2=-18\ cm/s

After collision first marble moves to the left with a velocity of 18 cm/s

i.e. v_1=-18\ cm/s

considering v_2 be the velocity of second marble after collision

The Coefficient of restitution is 1 for an elastic collision

e=\frac{v_2-v_1}{u_1-u_2}

Putting values

1=\frac{v_2-(-18)}{22.5-(-18)}\\22.5+18=v_2+18\\v_2=22.5\ m/s

So, the velocity of the second marble is 22.5 m/s to the right after the collision

(b)Initial kinetic energy =0.5\times 0.015\times (22.5\times 10^{-2})^2+0.5\times 0.015\times (18\times 10^{-2})^2=6.22\times 10^{-4}\ J

Final kinetic energy=

0.5\times 0.015\times (18\times 10^{-2})^2+0.5\times 0.015\times (22.5\times 10^{-2})^2=6.22\times 10^{-4}\ J

6 0
3 years ago
I will mark you as brainliest. if you answer my question
Shalnov [3]

First, let's list everything we have...

a = 1.83 m/s^2

F = 1870 N (converted from kN to N)

vi = 0 m/s (it says started from rest, therefore velocity starts at 0)

t = 16 s

1). "Force acting on the car" is a bit ambiguous because there are many forces. But I'm going to assume that they are looking for just a basic implementation of force equation:

F=ma

where:

F = force

m = mass

a = acceleration

2). I recommend memorizing your equations of motion, because once you know them this part is also just as easy:

v_f=v_i+at

where:

vf = final velocity

vi = initial velocity

a = acceleration

t = time

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3 years ago
It takes 50 seconds for Tyler to do 450 Joules of work. How much power did Tyler use?​
Bogdan [553]
Power=work/time
So,
Power =450/50=9watts
8 0
3 years ago
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How do the sun energy flow through the earth system
storchak [24]
The sun's energy flow through the earth's system by it moving through the earth's atmosphere.
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