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uysha [10]
4 years ago
9

If 300.0 grams of FeCr2O7 react, how many grams of O2 will be consumed

Chemistry
1 answer:
kvv77 [185]4 years ago
5 0
You are given 300 grams of FeCr2O7. You are required to get the mass of O2 in grams. The first thing to do is to find a reaction between FeCr2O7 and O2. The balanced chemical reaction is 2Fe + 6Cr + 21/2O2 -> Fe2(Cr2O7)3. The molar mass of Fe2(Cr2O7)3 is 759.65 grams per mole and 32 grams per mole for O2.  
<span>
300g Fe2(Cr2O7)3 (1 mol Fe2(Cr2O7)3/759.65 g Fe2(Cr2O7)3)(21/2 mol O2/1 mole Fe2(Cr2O7)3)(32 g O2/1 mole O2) = <u>132.7 g O2</u></span>
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1) Write the balanced chemical equation

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2) Write the molar ratios:

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3) Convert 0.15g of sodium carbonate to number of moles

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3b.- Calculate the number of moles of Na2CO3

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[0.0014 mol Na2CO3] * [2 mol HCl / 1 mol Na2CO3] = 0.0028 mol HCl

5) Calculate the volume of HCl from the definition of Molarity

Molarity, M = # moles / volume in liters

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0.028 liters * 1000 ml / liter = 28 ml.

Answer: 28 mililiters of 0.1 M HCl.
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