Answer:
None of these is correct.
Explanation:
The average speed can be derived from the sum of the total distance traveled and the total time taken.
Total distance = 4.9 + 1.9 = 6.8
Total time taken = 33 + 39 = 72
So;
Average speed =
=
= 0.014
None of the answer choices given is correct.
The answer is 6.
4=x-2
x=2+4
x=6
Answer:
P=(2 nm, 8mn)
Explanation:
Given :
Position of positively charged particle at origin, ![O=(0\ nm,0\ nm)](https://tex.z-dn.net/?f=O%3D%280%5C%20nm%2C0%5C%20nm%29)
Position of desired magnetic field, ![D\equiv(1\ nm,8\ nm)](https://tex.z-dn.net/?f=D%5Cequiv%281%5C%20nm%2C8%5C%20nm%29)
Magnitude of desired magnetic field, ![E=0\ N.C^{-1}](https://tex.z-dn.net/?f=E%3D0%5C%20N.C%5E%7B-1%7D)
Let q be the positive charge magnitude placed at origin.
<u>We know the distance between the two Cartesian points is given as:</u>
![d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_1-x_2%29%5E2%2B%28y_1-y_2%29%5E2%7D)
<u>For the electric field effect to be zero at point D we need equal and opposite field at the point.</u>
![\frac{1}{4\pi.\epsilon_0} \times \frac{q}{r^2 } =\frac{1}{4\pi.\epsilon_0} \times \frac{q}{r^2 }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%5Cpi.%5Cepsilon_0%7D%20%5Ctimes%20%5Cfrac%7Bq%7D%7Br%5E2%20%7D%20%3D%5Cfrac%7B1%7D%7B4%5Cpi.%5Cepsilon_0%7D%20%5Ctimes%20%5Cfrac%7Bq%7D%7Br%5E2%20%7D)
![\therefore (1-0)^2+(8-0)^2=r^2](https://tex.z-dn.net/?f=%5Ctherefore%20%281-0%29%5E2%2B%288-0%29%5E2%3Dr%5E2)
![r^2=65\ nm](https://tex.z-dn.net/?f=r%5E2%3D65%5C%20nm)
![r=\sqrt{65}](https://tex.z-dn.net/?f=r%3D%5Csqrt%7B65%7D)
as we know that the electric field lines emerge radially outward of a positive charge so the second charge will be at equally opposite side of the given point.
assuming that the second charge is placed at (x,y) nano-meters.
Therefore,
![x=2\times 1=2\ nm](https://tex.z-dn.net/?f=x%3D2%5Ctimes%201%3D2%5C%20nm)
and
![y=2\times 8=16\ nm](https://tex.z-dn.net/?f=y%3D2%5Ctimes%208%3D16%5C%20nm)