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sweet [91]
3 years ago
14

A closely wound rectangular coil of 80 turns has dimensions of 25 cm by 40 cm. The plane of the coil is rotated from a position

where it makes an angle of 37 degrees with a magnetic field of 1.10 T to a position perpendicular to the field. The rotation takes .06 s. What is the average emf induced in the coil?
Physics
1 answer:
ozzi3 years ago
3 0

Answer:

Average emf of coil is 58.4 V

Explanation:

Given :

No. of turns N = 80

Area of rectangular coil A = 0.25 \times 0.40 = 0.1 m^{2}

Magnetic field B = 1.10 T

Time of rotation \Delta t = 0.06 sec

From the faraday's law,

Average induced emf = N\frac{\Delta \phi}{\Delta t}

But flux through coil is given by,

 \phi = B A \cos \theta

So we write above equation,

Average induced emf = \frac{NBA( \cos \theta _{f} - \cos \theta _{i} )  }{\Delta t}

Where \theta _{f} = 0 and \theta _{i} = 53   ( \theta = 37  angle between plane and magnetic field)

Average induced emf = \frac{80 \times (1-0.602) \times 1.10 \times 0.1 }{0.06}

Average induced emf = 58.4 V

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