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Fiesta28 [93]
3 years ago
5

Need help really fast ! can give brainliest if correct :> thanks <3

Physics
2 answers:
Vlada [557]3 years ago
8 0

Answer:

2. Move faster

Explanation:

Because you lighten the weight and pushed at the same speed it is easier to push the 400-grams than the 800-grams.

Have a wonderful day!

Studentka2010 [4]3 years ago
6 0
The answer is 2 move faster
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Find the intensity of electromagnetic radiation at the surface of the sun (radius r=R=6.96×105kmr=R=6.96×105km). Ignore any scat
alisha [4.7K]

Answer:

I = 4.46*10^{16}W/m^2.

Explanation:

Intensity I of the electromagnetic radiation is given by

I = \dfrac{P}{4\pi r^2},

where r is the distance from the EM source (the center of the sun, in our case), and P is the power output of the sun and it has the value

P = 3.9 *10^{26}W.

Since the radius of the sun in meters is r = 6.96*10^8km, the intensity I of the electromagnetic radiation at the surface of the sun is

I = \dfrac{3.9*10^{26}W}{4\pi (6.96*10^8m)^2}\\\\\boxed{ I = 4.46*10^{16}W/m^2}

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3 years ago
Which is a disadvantage of using wind as an energy source?
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Answer:

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a lot of waste

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Consider a hydrogen atom in the n = 1 state. The atom is placed in a uniform B field of magnitude 2.5 T. Calculate the energy di
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Answer:

E=29\times 10^{-5}eV

Explanation:

For n-=1 state hydrogen energy level is split into three componets in the presence of external magnetic field. The energies are,

E^{+}=E+\mu B,

E^{-}=E-\mu B,

E^{0}=E

Here, E is the energy in the absence of electric field.

And

E^{+} and E^{-} are the highest and the lowest energies.

The difference of these energies

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\mu=9.3\times 10^{-24}J/T is known as Bohr's magneton.

B=2.5 T,

Therefore,

\Delta E=2(9.3\times 10^{-24}J/T)\times 2.5 T\\\Delta E=46.5\times 10^{-24}J

Now,

Delta E=46.5\times 10^{-24}J(\frac{1eV}{1.6\times 10^{-9}J } )\\Delta E=29.05\times 10^{-5}eV\\Delta E\simeq29\times 10^{-5}eV

Therefore, the energy difference between highest and lowest energy levels in presence of magnetic field is E=29\times 10^{-5}eV

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I believe the evidence for this theory is that:

The orbits surrounding Jupiter are highly elliptical which are off the plane of the ecliptic, and many of these moons are retrograde. This is very unlikely for moons or satellites which are formed during the planetary accretion. Hence comes the theory.

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