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vichka [17]
2 years ago
6

An airplane propeller is rotating at 2000 rev/min.

Physics
1 answer:
Fudgin [204]2 years ago
6 0

A 1 complete revolution corresponds to an angular displacement of 2π rad, or 360º. (So there are 180º for every π rad.) Also, there are 60 seconds to 1 minute. So, the angular velocity in rad/s is

(2000 rev/min) * (2π rad/rev) * (1/60 min/s) = 200π/3 rad/s

or approximately 209.44 rad/s.

B First convert the angular velocity to degrees per second (º/s):

(200π/3 rad/s) * (180/π º/rad) = 12,000 º/s

We want to find the time <em>t</em> it would take for the propeller to turn 36º:

36º = (12,000 º/s) <em>t</em>

==>  <em>t</em> = 36º / (12,000 º/s) = 3/1000 s

or approximately 0.003 s.

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Read 2 more answers
Salmon often jump waterfalls to reach their
PilotLPTM [1.2K]

The minimum velocity of the Salmon jumping at the given angle is 12.3 m/s.

The given parameters;

  • height of the waterfall, h = 0.432 m
  • distance of the Salmon from the waterfall, s = 3.17 m
  • angle of projection of the Salmon, = 30.8º

The time of motion to fall from 0.432 m is calculated as;

h = v_0_y + \frac{1}{2} gt^2\\\\0.432 = 0 + (0.5\times 9.8)t^2\\\\0.432 = 4.9t^2\\\\t^2 = \frac{0.432}{4.9} \\\\t^2 = 0.088\\\\t = \sqrt{0.088} \\\\t = 0.3 \ s

The minimum velocity of the Salmon jumping at the given angle is calculated as;

X = v_0_x t\\\\3.17 = (v_0\times cos(30.8)) \times 0.3\\\\10.567 = v_0\times cos(30.8)\\\\v_0 = \frac{10.567}{cos(30.8)} \\\\v_0 = 12.3 \ m/s

Thus, the minimum velocity of the Salmon jumping at the given angle is 12.3 m/s.

Learn more here: brainly.com/question/20064545

8 0
1 year ago
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