Question

6. A force of 40 N is applied to a 6 kg box of books. If the frictional force acting on the box is 16

Answer 1

Answer:

V = 40 m/s^2

Explanation:

horizontal force ,$F_h = 40N$

mass, m =  6kg

time, t = 10s

frictional force, $F_f = 16N$

net force $F = F_h - F_f = ma$

                 40N - 16N = 6 x a                      (1)

in this case you apply the equation of motion

the block is at rest, initial velocity is, U = 0

final velocity is is what we are looking for, V

$a = \frac{V - U}{t}$

since U is 0 we have

a  = V/t                                          (2)

subsituting (2) into (1)

$24 = \frac{6*V}{t}$

$24 = \frac{6*V}{10}$

cross multiply

240 = 6 x V

divide both sides by 6

V = 40 m/s^2