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-BARSIC- [3]
3 years ago
5

A charge +Q is located at the origin and a second charge, +4Q, is at distance (d) on the x-axis.

Physics
1 answer:
tatiyna3 years ago
5 0

Answer:

a)   x = ⅔ d , b) the charge must be negative, c) Q

Explanation:

a) In this exercise the force is electric between the charges, we are asked that the system of the three charges is in equilibrium, we use Newton's second law. Balance is on the third load that we are placing

         ∑ F = 0

        -F₁₂ + F₂₃ = 0

         F₁₂ = F₂₃

         

let's replace the values

        k Q Q / r₁₂² = k Q 4Q / r₂₃²

            Q² / r₁₂² = 4 Q² / r₂₃²

suppose charge 3 is placed at point x

        r₁₂ = x

        r₂₃ = d-x

             

we substitute

             1 / x² = 4 / (d-x) 2

             1 / x = 2 / (d-x)

             x = 2 (x-d)

             x = 2x -2d

            3x = 2d

              x = ⅔ d

b) The sign of the charge must be negative, to have an attractive charge on the two initial charges

c)  Q

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c) Y = Y_0 + V_0t + (1/2)at^2, and then we plug the values: Y_m_a_x = 32sin(25)*t - (1/2)*10*t^2 and we already have the time from "b)", so Y_m_a_x = [(32sin(25))*(32sin(25)/10)] - 5(32sin(25)/10)^2; then we just rearrange it Y_m_a_x = 10[(32sin(25))^2/100] - 5 [(32sin(25))^2/100] and finally Y_m_a_x = 5[(32sin(25))^2/100] = (32sin(25))^2/20
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Radio waves travel at a speed of 1.7 times 10^8 m/s through ice. A radio wave pulse sent into the Antarctic ice reflects off the
Nostrana [21]

The values with (1/2)(9.8 m/s2) (4 - X)^2 = (1.7 × 10^8 m/s) (X) —> We discover with the calculator X = 4.40 × 10^-7. The depth of the ice is then calculated by multiplying by the speed 74.8 m. Through ice, radio waves move at a speed of 1.7 x 108 m/s.

What is radio waves?

A radio wave pulse that is delivered into the Antarctic ice returns after reflecting off the bottom rock. A radio wave pulse that is transmitted into the Antarctic ice bounces off the subsurface rock and resurfaces. ice in Antarctica Through ice, radio waves move at a speed of 1.7 108 m/s. The rock reflects the radio wave pulse that was transmitted into the Antarctic ice. The amount of time that passed between the signal being sent and being received by the earth station.

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10 months ago
A baseball has a mass of 0.15kg .What is the net force on the ball if it's acceleration is 40.0m/sw
kvasek [131]

By Newton's second law, we have

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So, in order to give a 0.15kg body an acceleration of 40m/s^2, you need a force of

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3 years ago
A dog leaps horizontally off a 70 m cliff with a speed of 6 m/s, how far from the base will the dog land?
iris [78.8K]

Answer:

\Delta x=22.67786838m

Explanation:

Let's use projectile motion equations. First of all we need to find the travel time. So we are going to use the next equation:

y-y_0=v_o*sin(\theta)*t-\frac{1}{2}*t^2 (1)

Where:

y=Final\hspace{3}position\hspace{3}at\hspace{3}y-axis

y_o=Initial\hspace{3}position\hspace{3}at\hspace{3}y-axis

v_o=initial\hspace{3}velocity

t=travel\hspace{3}time

g=gravity\hspace{3}constant

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\theta=0

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Let's asume the gravity constant as:

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Now let's replace the data in (1)

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Isolating t:

t=\pm\sqrt{\frac{2*70}{9.8} } =3.77964473

Finally let's find the horizontal displacement using this equation:

\Delta x=v_o*cos(\theta)*t

Replacing the data:

\Delta x=6*1*3.77964473=22.67786838m

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julsineya [31]

Answer:

T = 235.134^{\textdegree}C

Explanation:

The process is modelled after the First Law of Thermodynamics:

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