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olga55 [171]
3 years ago
11

An organ pipe is made to play a low note at 27.5 Hz, the same as the lowest note on a piano. Assuming a sound speed of 343 m/s,

what length open-open pipe is needed? What length open-closed pipe would suffice?
Physics
1 answer:
timama [110]3 years ago
7 0

Answer:

The length of open-open pipe needed is 6.23 m

The length of open-close  pipe needed is 3.11 m

Explanation:

Fundamental frequency for standing wave mode of  an open- open pipe is given by

f=\frac{v}{2L}

where v is the velocity and L is the length

The length of open-open pipe needed is

L=\frac{v}{2f} \\L=\frac{343}{2\times 27.5} \\L=6.23 m

Fundamental frequency for standing wave mode of  an open- close pipe is given by

f=\frac{v}{2L}

The length of open-close pipe needed is

L=\frac{v}{2f} \\L=\frac{343}{2\times 27.5} \\L=6.23 m

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Answer:

a)    L = 3.29 10⁻⁴ H,  b)U = 5.33 10⁻²  J

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