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Tema [17]
3 years ago
15

A car increases its speed at a constant rate of 1.5 m/s2 as it rounds a curve of radius 200 m. The magnitude of the total accele

ration is 2.5 m/s2 . What is the car’s speed at this instant?

Engineering
1 answer:
vladimir2022 [97]3 years ago
7 0

Answer:

The car's instant speed is 20m/s

Explanation:

a = at + an

The above equation is a vector equation

a is the resultant acceleration

at   is the tangent acceleration

an  is the normal acceleration

See the attached diagram for solution

<h2 />

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what advantage might there be to having the encoder located on the motor side of the gearhead instead of at the output shaft of
UkoKoshka [18]

Answer:

The definition is defined in the clarification segment following the table, as per the particular circumstance.

Explanation:

  • In something like a closed-loop device, shaft encoders were being used, the output of which could be influenced either by encoder location. Most motors have been used for gearbox speed reduction (RPM). Assume there's also a gearbox reduction of 30:1 as well as the motor is already spinning at a higher 3000 rpm, then the outcome feature shaft speed would be 100 rpm.
  • This suggests that every other output shaft turning correlates to 30 input shaft flips, and even if the encoder contains 40 holes through its diameter, instead every output shaft revolution contributes to 40\times 30=1200 pulses. That implies an accuracy of 0.3 degrees of rotation of the final output shaft (\frac{360 \ degree}{1200} =0.3).  

Accuracy as well as reliability are thus given by positioning the encoder on the engine side instead of on the outcome shaft including its gear head.

6 0
3 years ago
The hoist of a crane consists of a 10 kW electric motor running at 1440 rpm drivine 300 mm diameter drunn through a 60:1 gear re
MissTica

Answer:

 Load =  2.42 tons

Lifting speed = 24 RPM

Explanation:

Given that

Power=10 KW

Efficiency = 90%

So the actual power,P=0.9 x 10 =9 KW

Speed of motor = 1440 RPM

Diameter of drum = 300 mm

radius =150 mm

G=60:1

Lets take speed of drum =N

We know that

G=\dfrac{Speed\ of\ motor}{Speed\ of\ drum}

60=\dfrac{1440}{N}

N=24 RPM

We know that

P=\dfrac{2\pi NT}{60}

Where T is the torque

9000=\dfrac{2\pi \times 24\times T}{60}

T=3580.98 N.m

Lets take load =F

So T= F x r

3580.98 = F x 0.15

F=23.87 KN

We know that

1 KN=0.109 tons

So 23.87 KN= 2.42 tons

So the load =  2.42 tons

Lifting speed = 24 RPM

8 0
3 years ago
Ayden read 84 pages in 2 hours. At that rate, how many pages can he read in 5 hours
Papessa [141]

Answer:210

Explanation:

Divide 84 by 2 and then multiply by 5 by that number

3 0
4 years ago
Read 2 more answers
Your Java program will be reading input from a file name strInput.txt. Each record contains String firstname String lastName Str
stiks02 [169]

Answer:

The program requires that you have the specified input files and it reads from each file at a time and processes salary in digits, states the city, state and bonus with respective first and last name as requested in the question. Note that you must have access to the mentioned output files for the program to work properly. Below is the java version of the program.

import java.io.File;

import java.io.FileNotFoundException;

import java.io.PrintWriter;

import java.util.Scanner;

class Driver

{

public static void main(String[] args) throws FileNotFoundException

{

Scanner sc = new Scanner(new File("strInput.txt"));

PrintWriter pd = new PrintWriter(new File("strOutputD"));

PrintWriter prf = new PrintWriter(new File("strOutputRF"));

String firstname = "", lastname = "", strSalary = "", status = "", cityState = "", city = "", state = "";

double salary = 0, bonus = 0;

int incorrectRecords = 0;

int dRecords = 0;

int fRecords = 0;

while(sc.hasNextLine())

{

firstname = sc.next();

lastname = sc.next();

strSalary = sc.next();

status = sc.next();

cityState = sc.next();

if(!status.equals("D") && !status.equals("F"))

{

System.out.println("Records is neither D nor F. Skipping this...");

incorrectRecords++;

continue;

}

else if(status.equals("D") || status.equals("F"))

{

char c = ' ';

int i = 0;

for(i=0; i<strSalary.length() && c != '.'; i++)

{

c = strSalary.charAt(i);

if(!Character.isDigit(c))

{

System.out.println("Char at position " + (i+1) + " in salary is not a digit");

incorrectRecords++;

continue;

}

}

if(c == '.')

{

if(i+1 == strSalary.length()-1)

{

if(!Character.isDigit(strSalary.charAt(i)))

{

System.out.println("Char at position " + (i+1) + " in salary is not a digit");

incorrectRecords++;

continue;

}

if(!Character.isDigit(strSalary.charAt(i+1)))

{

System.out.println("Char at position " + (i+1+1) + " in salary is not a digit");

incorrectRecords++;

continue;

}

}

else

{

System.out.println("Period is in the wrong position. Expected at " + (strSalary.length()-3) + " but found at " + (i+1));

continue;

}

}

city = cityState.split(",")[0];

state = cityState.split(",")[1];

salary = Double.parseDouble(strSalary);

if(status.equals("D"))

{

bonus = salary * 0.125;

dRecords++;

pd.write(firstname + " " + lastname + " " + status + " " + salary + " " + bonus + " " + city + " " + state);

}

else

{

bonus = salary * 0.18;

fRecords++;

prf.write(firstname + " " + lastname + " " + status + " " + salary + " " + bonus + " " + city + " " + state);

}

}

}

System.out.println("No of D records : " + dRecords);

System.out.println("No of F records : " + fRecords);

System.out.println("No of incorrect records : " + incorrectRecords);

}

}

6 0
3 years ago
The knob at the front of the miter saw about belt height is used to adjust the miter angle true or false
irinina [24]

Answer:

True.

Explanation:

There are two basic saw angles, and the little nob on the front controls the one angle, and the one on the rear controls the other.

4 0
3 years ago
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