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3 years ago

If the temperature of a piece of steel decreases, what happens to its density? (1 point)

Physics

2 answers:

Lelechka [254]3 years ago

5 0

temperature decreases the density will increase.

zlopas [31]3 years ago

3 0

As temperature decreases, the steel will contract (volume decreases) thereby, an increase in Density.

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A car of mass 1600 kg traveling at 27.0 m/s is at the foot of a hill that rises vertically 135 m after travelling a distance of

Zarrin [17]

Answer:

Neglecting any frictional losses, the average power delivered by the car's engine is 10565 W

Explanation:

The energy conservation law indicates that the energy must be the same at the bottom of the hill and at the top of the hill.

The energy at the bottom is only the Kinect energy (K_1) of the car in motion, but in the top, the energy is the sum of its Kinect energy (K_2), potential energy (P) and the work (W) done by the engine.

$K_1 = K_2 + P + W$

then, the work done by the engine is:

$W = K_1 - K_2 - P$

The formulas for the Kinetic and potential energy are:

$K=\frac{1}{2}mV^2\\P=mgh$

where, m is the mass of the car, V the velocity, g the gravity and h is the elevation of the hill.

Using the formulas:

$W=\frac{1}{2}mV_1^2-\frac{1}{2}mV_2^2-mgh$

Replacing the values:

$W=\frac{1}{2}(1600Kg)(27m/s)^2-\frac{1}{2}(1600Kg)(14m/s)^2-(1600Kg)(9.8m/s^2)(135m)\\W=-1690400 J$

The negative of this value indicates the direction of the work done, but for the problem, you only care about the magnitude, so the power is W=1690400 J. Now, the power is equal to work/time so you need to find the time the car took to get to the top of the hill.

The average speed of the car is (27+14)/2=20m/s, and t=d/v so the time is:

$t=\frac{3200m}{20m/s}=160s$

the power delivered by the car's engine was:

$power=\frac{work}{time}=\frac{1690400J}{160s}=10565W$

8 0

3 years ago

Imagine that I have a ping-pong ball and a bowling ball resting on the floor of our classroom. I go up to the bowling ball and g

MatroZZZ [7]

Answer:

the speed and aceleration of the ping pong ball is greater than that of the bowling ball.

Explanation:

We can analyze this exercise from several points of view, if we use Newton's second law

Bowling ball

F = M a₁

pingpongg ball

F = m a₂

as the forces the same

M a₁ = m a₂

a₂ = $\frac{M}{m}$ a₁

Since the mass of the bowling ball is much greater than the ping pong ball,

a₂ »a₁

so the acceleration of the ping pong ball is much greater than the acceleration of the bowling ball.

If we use the relationship of momentum and momentum, assuming that the time for the two cases is the same and that both start from rest

Bowling ball

I = F t = Δp

I = M (v₁ - v₀)

Ping pong ball

I = F t = Δp

I = m (v₂ -v₀)

the impulse itself

M v₁ = m v₂

v₂ = $\frac{M }{ m}$ v₁

so we conclude that the speed of the ping pong ball is much greater than the speed of the bowling ball.

In conclusion the speed and aceleration of the ping pong ball is greater than that of the bowling ball.

4 0

2 years ago

The diagram shows a position-time graph.

Vaselesa [24]

'Displacement' means the distance and direction from the start-point to the end-point, regardless of what happened along the way.

This object started out at 1 meter and ended up at zero meter.

The change it racked up from start to finish is 1 meter, and the direction is backwards.

The displacement is 1 meter backwards, or -1 meter .

9 0

3 years ago

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What is simple harmonic motion

Irina-Kira [14]

Simple harmonic motion is defined as a periodic motion of a point along a straight line. It’s acceleration is always towards a fixed point in that line and is proportional to its distance from that point.

5 0

3 years ago

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The ___ of an object measures the amount of matter in t g e object

hram777 [196]

I believe it is the mass of an object. The question is oddly asked

4 0

3 years ago