1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
leva [86]
3 years ago
8

PHYSICAL SCIENCE HELP

Chemistry
1 answer:
nikitadnepr [17]3 years ago
7 0

Answer:

the magnitude of gravitational force would be 20 N

Explanation:

therefore on a body of mass m by earth is \frac{GMm}{r^{2}}

where M  is the mass of earth m is the mass of body, G is the gravitational constant and r is the distance of seperation from centre of earth.

therefore F =m\times \frac{GM}{r^{2}}=mg=10m

therefore F = 20 N.

You might be interested in
DNA transcription-to-translation # 1 Homework Unanswered Due in 4 days Given the following sequence of the coding strand, writte
uysha [10]

Explanation:

Translation is the process by which a polypeptide is polymerized from genetic information.

Firstly we have to make a transcription from the coding DNA strand to a single RNA strand (mRNA). RNA pol reads from 5' to 3' of the template strand and nucleotides are added by complementarity ( Adenine with Uracil, Thymine with Adenine and Cytosine with Guanine, Guanine with Cytosine).

DNA:  5'-  CGTTATGTGGACTCTCTGGTATGACTCACCTTAT -3'

mRNA: 5'-GCAAUACACCUGAGAGACCAUACUGAGUGGAAUA -3'

mRNA goes to the ribosomes where translation takes place. The enzyme will read every three letters (codon) starting at the start codon sequence (TAC in DNA, AUG in mRNA). According to codons tRNA carrying the amino acids will place it (by complementary to their anticodon) and the enzyme will join it to the nascent polypeptide or protein.

In order to do this we need to look up the genetic code and assign the proper amino acids.

Unfortunately the given strand does not have a start codon TAC codifying for initial methionine.

3 0
3 years ago
Hello<br>Thank you for not answering my question
julsineya [31]
**Visible confusion** no problem
4 0
3 years ago
15 grams of sodium reacts with a certain amount of chlorine to yield 37 grams of sodium chloride, as shown below.
ale4655 [162]

Answer: 22g of chlorine would be needed to carry out this synthesis reaction

Explanation:

A synthesis reaction is one in which two or more than two elements combine together to forma single product.

Na+Cl\rightarrow NaCl

The atoms present in the reactants are found on the product side. According to the law of conservation of mass, the number of atoms on both sides of the arrow must be same as the total mass must be conserved.

15 grams of sodium reacts with 22 grams of chlorine to yield 37 grams of sodium chloride. Thus 22g of chlorine would be needed to carry out this synthesis reaction.

4 0
3 years ago
2 NO + O22 NO2 is second order in NO and first order in O2. Complete the rate law for this reaction in the box below. Use the fo
riadik2000 [5.3K]

Answer : The value of rate of reaction is 1.35\times 10^{-8}Ms^{-1}

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The given chemical equation is:

2NO+O_2\rightarrow 2NO_2

Rate law expression for the reaction is:

\text{Rate}=k[NO]^a[O_2]^b

As per question,

a = order with respect to NO  = 2

b = order with respect to O_2 = 1

Thus, the rate law becomes:

\text{Rate}=k[NO]^2[O_2]^1

Now, calculating the value of rate of reaction by using the rate law expression.

Given :

k = rate constant = 9.87\times 10^3M^{-2}s^{-1}

[NO] = concentration of NO = 7.86\times 10^{-3}M

[O_2] = concentration of O_2= 2.21\times 10^{-3}M

Now put all the given values in the above expression, we get:

\text{Rate}=(9.87\times 10^3M^{-2}s^{-1})\times (7.86\times 10^{-3}M)^2\times (2.21\times 10^{-3}M)^1

\text{Rate}=1.35\times 10^{-8}Ms^{-1}

Hence, the value of rate of reaction is 1.35\times 10^{-8}Ms^{-1}

7 0
3 years ago
50.0 ml of 0.010m naoh was titrated with 0.50m hcl using a dropper pipet. if the average drop from the pipet has a volume of 0.0
creativ13 [48]

25 drops of acid is required to neutralize the 50.0 ml of 0.010m of NaOH in the experiment.

The equation of the reaction is;

NaOH(aq) + HCl(aq) ---------> NaCl(aq) + H2O(l)

We can use the titration formula;

CAVA/CBVB = NA/NB

CA= concentration of acid

VA = volume of acid

CB = concentration of base

VB = volume of base

NA = number of moles of acid

NB = number of moles of base

CB = 0.010 M

VB = 50.0 ml

CA = 0.50 M

VA = ?

NA = 1

NB = 1

Substituting values;

CAVANB = CBVBNA

VA =  0.010 ×  50.0 × 1/ 0.50 × 1

VA = 1 ml

Since the total volume of acid used is 1 ml and each drop contains 0.040 ml

The number of drops required is 1ml/0.040 ml = 25 drops

Learn more: brainly.com/question/1527403

4 0
3 years ago
Other questions:
  • Is this right?If not what did I do wrong ?
    5·1 answer
  • What binary compound would be formed from barium ions and fluoride ions?
    5·2 answers
  • Windblown________ can wear away rock
    12·2 answers
  • Adrenaline is a hormone secreted in the body's effort to slow the heart rate.<br> True<br> False
    15·1 answer
  • What mass of sodium benzoate should be added to 150.0 ml of a 0.15 m benzoic acid solution in order to obtain a buffer with a ph
    14·1 answer
  • 9. Based on your work with benzoic acid, show the reaction between salicylic acid and potassium hydroxide. Label the acid, base,
    10·1 answer
  • Which of the following statements about gases is not correct? A. They have much lower densities than solids or liquids. B. They
    9·1 answer
  • A certain first-order reaction is 27.5 percent complete in 8.90 min at 25°C. What is its rate constant?
    9·1 answer
  • Why are the fields of science and math so independent?
    12·1 answer
  • PLEASE HELP ME!!
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!