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Leto [7]
3 years ago
7

If a 40-kg object is moving with a velocity of 65 m/s to the right, for how many minutes must a force of 4n be applied in the op

posite direction to result in a final velocity of the object of 10 m/s in the opposite direction?
Physics
1 answer:
AVprozaik [17]3 years ago
6 0
F = ma
4 = 40a
a = 0.1 m/s

v = u + at
-10 = 65 - 0.1t
t = 750s = 12.5 min
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A 117 kg horizontal platform is a uniform disk of radius 1.61 m and can rotate about the vertical axis through its center. A 62.
Ivenika [448]

Answer:

I_syst = 278.41477 kg.m²

Explanation:

Mass of platform; m1 = 117 kg

Radius; r = 1.61 m

Moment of inertia here is;

I1 = m1•r²/2

I1 = 117 × 1.61²/2

I1 = 151.63785 kg.m²

Mass of person; m2 = 62.5 kg

Distance of person from centre; r = 1.05 m

Moment of inertia here is;

I2 = m2•r²

I2 = 62.5 × 1.05²

I2 = 68.90625 kg.m²

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Distance of Dog from centre; r = 1.43 m

I3 = 28.3 × 1.43²

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I_syst = I1 + I2 + I3

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8 0
3 years ago
Answer for a thanks
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7 0
3 years ago
7. Calculations.
kotykmax [81]

Answer:

5 ms-2

Explanation:

F = ma

F = 100N

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100 = 20a

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4 0
4 years ago
If you were to stand in the exact center of a rotating disc, you would only have what kind of
Dmitriy789 [7]

Answer:

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shutvik [7]

Answer:

49.3 m/s

Explanation:

The momentum is defined as the product of the object velocity and its mass.

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For the car to have the same momentum, its speed must be

v_c = P_t/m_c = 54720 / 1110 = 49.3 m/s

6 0
4 years ago
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