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Leto [7]
2 years ago
7

If a 40-kg object is moving with a velocity of 65 m/s to the right, for how many minutes must a force of 4n be applied in the op

posite direction to result in a final velocity of the object of 10 m/s in the opposite direction?
Physics
1 answer:
AVprozaik [17]2 years ago
6 0
F = ma
4 = 40a
a = 0.1 m/s

v = u + at
-10 = 65 - 0.1t
t = 750s = 12.5 min
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Crazy boy [7]

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<em><u>In how many seconds will it reach the ground?</u></em>

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<em><u>How far from the point of projection would it strike? </u></em>

We want to find the displacement in the x-direction for the body.

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Substitute known values into the equation. Remember that we want to use the horizontal component of the initial velocity and that the acceleration in the x-direction is 0 m/s².

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