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3 years ago

7

If a 40-kg object is moving with a velocity of 65 m/s to the right, for how many minutes must a force of 4n be applied in the op

posite direction to result in a final velocity of the object of 10 m/s in the opposite direction?

1 answer:

AVprozaik [17]3 years ago

6 0

F = ma
4 = 40a
a = 0.1 m/s

v = u + at
-10 = 65 - 0.1t
t = 750s = 12.5 min

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4 years ago

Read 2 more answers

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Formula used:

y = $\frac{m \times \lambda \times D}{d}$

y = distance of first bright band from central maxima

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Solution:

distance of first bright band from central maxima is given by,

y = $\frac{m \times \lambda \times D}{d}$

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$\lambda$ = wavelength

Thus,

d = $\frac{m \times \lambda \times D}{y}$

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4 years ago