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Ipatiy [6.2K]
3 years ago
7

The efficiency of transformer is not 100%why?​

Physics
1 answer:
anastassius [24]3 years ago
4 0

Answer:

Hysteresis, Eddy current, flux leakage and resistance of winding are those four reasons. It is impossible to overcome this four reasons, Hence transformer never be 100% efficient.

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A 1100 kg car rounds a curve of radius 68 m banked at an angle of 16 degrees. If the car is traveling at 95 km/h, will a frictio
Mariulka [41]

Answer:

Yes. Towards the center. 8210 N.

Explanation:

Let's first investigate the free-body diagram of the car. The weight of the car has two components: x-direction: towards the center of the curve and y-direction: towards the ground. Note that the ground is not perpendicular to the surface of the Earth is inclined 16 degrees.

In order to find whether the car slides off the road, we should use Newton's Second Law in the direction of x: F = ma.

The net force is equal to F = \frac{mv^2}{R} = \frac{1100\times (26.3)^2}{68} = 1.1\times 10^4~N

Note that 95 km/h is equal to 26.3 m/s.

This is the centripetal force and equal to the x-component of the applied force.

F = mg\sin(16) = 1100(9.8)\sin(16) = 2.97\times10^3

As can be seen from above, the two forces are not equal to each other. This means that a friction force is needed towards the center of the curve.

The amount of the friction force should be 8.21\times 10^3~N

Qualitatively, on a banked curve, a car is thrown off the road if it is moving fast. However, if the road has enough friction, then the car stays on the road and move safely. Since the car intends to slide off the road, then the static friction between the tires and the road must be towards the center in order to keep the car in the road.

5 0
4 years ago
__________ receptors detect presence of acids in substances, whereas __________ receptors detect sodium in substances. A. Sour .
Irina18 [472]

Answer:

A sour and salt

Explanation:

7 0
4 years ago
Read 2 more answers
Two boys with masses of 40 kg and 60 kg stand on a horizontal frictionless surface holding the ends of a light 10-m long rod. Th
kari74 [83]

When they meet the 40-kg boy will have moved a distance of 6 m.

Displacement of the 40 kg boy

The displacement of the 40 kg boy is calculated from the principle of center mass.

X(40 kg) = (60 x 10 m    +  40 x 0)/(40 kg + 60 kg)

X(40 kg) = (600)/(100) = 6 m

X(60 kg) = (60 x 0    +  40 x 10 m)/(40 kg + 60 kg)

X(60 kg) = (400)/(100) = 4 m

Thus, when they meet the 40-kg boy will have moved a distance of 6 m.

Learn more about center mass here: brainly.com/question/13499822

#SPJ1

7 0
2 years ago
In the one pully system when you move the mass from the 20 cm mark to the 15 cm mark, it moves 5 cm. How far did you pull the st
drek231 [11]

Answer:

5 cm

Explanation:

4 0
3 years ago
Fe has the electron configuration [Ar]3d64s2. What is the magnitude of the orbital angular momentum for its most energetic elect
salantis [7]

Answer : The magnitude of the orbital angular momentum for its most energetic electron is, \sqrt{6}\hbar

Explanation :

The formula used for orbital angular momentum is:

L=\sqrt{l(l+1)}\hbar

where,

L = orbital angular momentum

l = Azimuthal quantum number

As we are given the electronic configuration of Fe is, [Ar]3d^64s^2

Its most energetic electron will be for 3d electrons.

The value of azimuthal quantum number(l) of d orbital is, 2

That means, l = 2

Now put all the given values in the above formula, we get:

L=\sqrt{2(2+1)}\hbar

L=\sqrt{6}\hbar

Therefore, the magnitude of the orbital angular momentum for its most energetic electron is, \sqrt{6}\hbar

7 0
3 years ago
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