Why can't cells get any glucose directly from the small intestine?

2 answers:

8 0

It's because a glucose molecule is too large to pass through a cell membrane via simple diffusion. Instead, cells assist glucose diffusion through facilitated diffusion and two types of active transport.

I really predicated if you give me Brainliest

Alik [6]3 years ago

6 0

Glucose molecule is too large to pass through a cell membrane via simple diffusion.

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What is the mass of 5 moles of gold

Serhud [2]

First of all, we know that one mole is equal to the atomic number of an element.

The atomic number of gold is 197.0g Au

And we need to find 5 moles.

5 * 197.0 g Au = 985.0g

Grams is used to measure mass.

Answer: 985.0g

8 0

3 years ago

Read 2 more answers

Which of the following statements is true about the scientific process?

KiRa [710]

The best and most correct answer among the choices provided by your question is the third choice or letter C.
The statement "Your hypothesis must be testable." is true about the scientific process.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

4 0

3 years ago

A 150-W lamp is placed into a 120-V ac outlet. What is the peak current?

devlian [24]

Answer:

Explanation:

Formula

W = I * E

Givens

W = 150

E = 120

I = ?

Solution

150 = I * 120 Divide by 120

150/120 = I

5/4 = I

I = 1.25

Note: This is an edited note. You have to assume that 120 is the RMS voltage in order to go any further. That means that the peak voltage is √2 times the size of 120. The current has the same note applied to it. If the voltage is its rms value, then the current must (assuming the properties of the bulb do not change)

On the other hand, if the voltage is the peak value at 120 then 1.25 will be correct.

However I would go with the other answerer's post and multiply both values by √2

3 0

4 years ago

Read 2 more answers

A steady electric current flows through a wire. If 9.0 C of charge passes a particular spot in the wire in a time period of 2.0

defon

1) Current: 4.5 A

2) Time taken: 4.7 s

Explanation:

The electric current intensity is defined as the rate at which charge flows in a conductor; mathematically:

$I=\frac{q}{t}$