Answer:
2 m/s
Explanation:
From the conservation of momentum, the initial momentum of the system must be equal to the final momentum of the system.
Let the 10.00 kg mass be 
and the 12.0 kg mass be 
. When they collide and stick, they have a combined mass of 
.
Momentum is given by 
. Set up the following equation:
, where 
is the desired final velocity of the masses.
Call the right direction positive. To indicate the 12.0 kg object is travelling left, its velocity should be substitute as -8.00 m/s.
Solving yields:
Static friction is the friction between an object at rest and the surface on which it is resting on.
Kinetic friction is the friction between a moving object and the surface on which it moves.
Hopefully you understood and this helps :)
The answer is C
The colour that you see is what is being reflected and the colour that you don't see is what is being absorbed. In this case, you don't see any colour, so all wavelengths are being absorbed.
Answer:
a The velocity of the third particle is 
b The total kinetic energy increase 
Explanation:
To solve this question we are going to be using the concept of conservation of momentum which is mathematically represented as
From the question
Mass of unstable atomic nucleus 
Mass of x-axis particle 
Velocity of x-axis particle 
Mass of y-axis particle 
Velocity of y-axis particle 
Since the initial mass is known we can obtain the mass of the third particle
Using the conservation of mass mathematical expression
Using the mathematical expression above for conservation of momentum
The above is the vector solution now to obtain the value in numeric form we evaluate the magnitude of the vector
To obtain the total increase in kinetic energy which is mathematically represented as
![E =\frac{1}{2} [(5.20*10^{-27})(6.0*0^{6})^2 + (8.44*10^{-27})(4.00*10^6)^2+\\\\(2.16*10^{-27})(21.285*10^6)^2]](https://tex.z-dn.net/?f=E%20%3D%5Cfrac%7B1%7D%7B2%7D%20%5B%285.20%2A10%5E%7B-27%7D%29%286.0%2A0%5E%7B6%7D%29%5E2%20%2B%20%288.44%2A10%5E%7B-27%7D%29%284.00%2A10%5E6%29%5E2%2B%5C%5C%5C%5C%282.16%2A10%5E%7B-27%7D%29%2821.285%2A10%5E6%29%5E2%5D)
