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Ronch [10]
4 years ago
15

What is smallest unit of time.Express its value

Physics
2 answers:
Sever21 [200]4 years ago
7 0

1s = 1.0 \times  {10}^{ - 24} s \:  \: = 1ys
1 ys is the smallest unit of time.
IRISSAK [1]4 years ago
4 0
1ys is the smallest unit of time
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A 10.00 kg mass is moving to the right with a velocity of 14.0 m/s. A 12.0 kg mass is moving to the left with a velocity of 8.00
Basile [38]

Answer:

2 m/s

Explanation:

From the conservation of momentum, the initial momentum of the system must be equal to the final momentum of the system.

Let the 10.00 kg mass be m_1 and the 12.0 kg mass be m_2. When they collide and stick, they have a combined mass of m_1+m_2.

Momentum is given by p=mv. Set up the following equation:

\displaystyle m_1v_1+m_2v_2=(m_1+m_2)v_f, where v_f is the desired final velocity of the masses.

Call the right direction positive. To indicate the 12.0 kg object is travelling left, its velocity should be substitute as -8.00 m/s.

Solving yields:

10\cdot 14 + 12\cdot (-8)=(10+12)v_f\\\implies v_f=\boxed{2 \text{ m/s}}

4 0
2 years ago
2 What can you Infer about this source of electricity?
anzhelika [568]

Answer:i think it's d

Explanation:

6 0
3 years ago
What is the difference between static and Kenetic friction?
rusak2 [61]
Static friction is the friction between an object at rest and the surface on which it is resting on.

Kinetic friction is the friction between a moving object and the surface on which it moves.

Hopefully you understood and this helps :)
3 0
4 years ago
How does light interact with the fur of a black cat?
Rina8888 [55]

The answer is C

The colour that you see is what is being reflected and the colour that you don't see is what is being absorbed. In this case, you don't see any colour, so all wavelengths are being absorbed.

6 0
3 years ago
An unstable atomic nucleus of mass 1.58 10-26 kg initially at rest disintegrates into three particles. One of the particles, of
lara31 [8.8K]

Answer:

a The velocity of the third particle is v_3 = (-15.629*10^{6}i -14.45*10^{6}j)\ m/s

b The total kinetic energy increase E = 6.50 *10^{-13} J

Explanation:

To solve this question we are going to be using the concept of conservation of momentum which is mathematically represented as

            m_1v_1 +m_2v_2 +m_3v_3 = 0

From the question

        Mass of  unstable atomic nucleus m_0= 1.58 *10^{-26} kg

        Mass of  x-axis particle m_1 = 8.44* 10^{-27} kg

        Velocity of x-axis particle v_ 1 =  4.00* 10^6 m/s

         Mass of  y-axis particle  m_2 =5.20* 10^{-27} kg

            Velocity of y-axis particle  v_2 = 6.00 *10^6 m/s

 Since the initial mass is known we can obtain the mass of the third particle  

 Using the conservation of mass mathematical expression

                m_3 = m_0 - (m_1 +m_2)

                  m_3 = 1.58 *10^{-26}  - ( 8.44* 10^{-27} + 5.20* 10^-27)

                        = 2.16 *10 ^{-27}kg

Using the mathematical expression above for conservation of momentum

               (8.44 * 10^{-27})( 4.00* 10^6i) + (5.20 *10^{-27})(6.00* 10^6j) +(2.16*0^{-27})v_3 =0

            v_3 = (-15.629*10^{6}i -14.45*10^{6}j)\ m/s

The above is the vector solution now to obtain the value in numeric form we evaluate the magnitude of the vector

         Mag  = \sqrt{(15.629*10^6)^2 +(14.45*10^6)^2}

                = 21.285*10^6 \ m/s

To obtain the total increase in  kinetic energy which is mathematically represented as

         E = \frac{1}{2}m_1v_1 +  \frac{1}{2}m_2v_2 + \frac{1}{2} m_3 v_3

         E =\frac{1}{2} [(5.20*10^{-27})(6.0*0^{6})^2 + (8.44*10^{-27})(4.00*10^6)^2+\\\\(2.16*10^{-27})(21.285*10^6)^2]

              = 6.50 *10^{-13} J

5 0
3 years ago
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