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denis23 [38]
3 years ago
7

In the reaction at Blood Falls, iron and oxygen combine to form iron oxide, which is called rust (water is also present). The re

actants are ,
A] Oxygen and iron oxide
B] iron ad iron oxide
C] Oxygen and iron

and the product is

A] iron
B] Oxygen
C] Iron oxide.

i need answers to boh blanks please.
Physics
2 answers:
notka56 [123]3 years ago
8 0

Answer:The reactants are Oxygen and iron.

The product is Iron oxide.

Explanation:

When iron and oxygen reacts with each other produce iron oxide which reddish brown in color. This reddish brown iron oxide is often refereed to as Rust.

4Fe+3O_2\rightarrow 2Fe_2O_3(\text{reddish brown})

The Reactants are iron and oxygen.

The product is iron oxide

uranmaximum [27]3 years ago
3 0
Reactant is<span> a substance that is in a chemical </span>reaction<span>. Product is a substance that is produced by the chemical </span>reaction. A chemical change that you are familiar with isrust<span>. In this chemical </span>reaction<span>, </span>oxygen<span> and </span>iron<span>, which are the </span>reactants,combine to form<span> a product called </span>iron oxide(rust<span>)
(Mark me as brainiest, vote, and give thanks! Trying to rank up!)</span>
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a-b

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123.6grams-115.972grams = 7.6grams

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The result of 7.628 will be expressed as 7.6 to have the correct number of significant figures.          

 

Notice how that can be express in units of kilograms too since there is 1000 gram in 1 kilogram:

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A pin-supported, vertically-oriented 1-m long thin rod is struck by a pellet at m down from the pin at the top. The mass of the
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Answer:

the angular velocity of the rod immediately after being struck by the pellet, provided that the pellet gets lodged in the rod is = 0.5036 k` rad/s

Explanation:

Using the conservation of momentum of approach.

From the question; the pellet is hitting at a distance of 0.4 m down from the point of rotation of the rod.

So, the angular momentum of the system just before the collision occurs  with respect to the axis of the rotation is expressed by the formula:

L_i ^ { ^  \to } = mp ( r_y } ^ { ^  \to }  * v_{pi}  ^ { ^  \to } )    ----- equation (1)

The position vector can now be :

x ^ { ^  \to } = - 0.4 \ j \ m

Also, given that :

v_{p,i}  ^ { ^  \to } = (280 \ i - 350 \  j)  \ m/s

Replacing the value into above equation (1); we have:

L_i ^ { ^  \to } =0.012 ((- \ 0.4 \  j) *(280 \ i - 350 \ j ))

L_i ^ { ^  \to } =0.012 * 112 \  k    (by using cross product )

L_i ^ { ^  \to } = 1.344 k` \  \  kg  m^2 s^{-1}

However; the moment of inertia of the rod about the axis of rotation is :

I_{rod} = \frac{1}{3}m_rl^2  \\ \\ I_{rod} = \frac{1}{3}*8*1^2 \\ \\ I_{rod} = \frac{8}{3} \ \  kg  \ m^2

Also, the moment of inertia of the pellet about the axis of rotation is:

I_{pellet} = m_pr_y^2 \\ \\ I_{pellet} = 0.012 *0.4^2  \\ \\ I_{pellet} = 1.92*10^{-3} kg . m^2

So, the moment of inertia of the rod +pellet system is:

I = I_{rod}+I_{pellet}

I =( \frac{8}{3}+1.92 *10^{-3} )kg. m^2

I = 2.6686 \  kg. m^2

The final angular momentum is :

L_f ^ {^ \to}  = I \omega { ^ {^ \to} } = 2.6686 \  \omega  ^ {^ \to}

The angular velocity of the rod \omega is determined by equating the angular momentum just before the collision with the final angular momentum (i.e after the collision).

So;

L_f ^ {^ \to} = L_i ^ { ^ \to}

2.6686 \omega ^ {^ \to} = 1.344 \ k ^ {^ \to}

\omega  ^ {^ \to} = \frac{1.344 \ k`}{2.6686}

= 0.5036 k` rad/s

Hence; the angular velocity of the rod immediately after being struck by the pellet, provided that the pellet gets lodged in the rod is = 0.5036 k` rad/s

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