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denis23 [38]
3 years ago
7

In the reaction at Blood Falls, iron and oxygen combine to form iron oxide, which is called rust (water is also present). The re

actants are ,
A] Oxygen and iron oxide
B] iron ad iron oxide
C] Oxygen and iron

and the product is

A] iron
B] Oxygen
C] Iron oxide.

i need answers to boh blanks please.
Physics
2 answers:
notka56 [123]3 years ago
8 0

Answer:The reactants are Oxygen and iron.

The product is Iron oxide.

Explanation:

When iron and oxygen reacts with each other produce iron oxide which reddish brown in color. This reddish brown iron oxide is often refereed to as Rust.

4Fe+3O_2\rightarrow 2Fe_2O_3(\text{reddish brown})

The Reactants are iron and oxygen.

The product is iron oxide

uranmaximum [27]3 years ago
3 0
Reactant is<span> a substance that is in a chemical </span>reaction<span>. Product is a substance that is produced by the chemical </span>reaction. A chemical change that you are familiar with isrust<span>. In this chemical </span>reaction<span>, </span>oxygen<span> and </span>iron<span>, which are the </span>reactants,combine to form<span> a product called </span>iron oxide(rust<span>)
(Mark me as brainiest, vote, and give thanks! Trying to rank up!)</span>
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A merry-go-round with a rotational inertia of 600 kg m2 and a radius of 3. 0 m is initially at rest. A 20 kg boy approaches the
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\boxed{\omega = 0.38 rad/sec}

We can use the conservation of angular momentum to solve.

\large\boxed{L_i = L_f}

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We can begin by writing out the scenario as a conservation of angular momentum:

I_m\omega_m + I_b\omega_b = \omega_f(I_m + I_b)

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\omega_f = final angular velocity of COMBINED objects (rad/sec)

I_b = moment of inertia of boy (kgm²)

\omega_b= angular velocity of the boy (rad/sec)

The only value not explicitly given is the moment of inertia of the boy.

Since he stands along the edge of the merry go round:

I = MR^2

We are given that he jumps on the merry-go-round at a speed of 5 m/s. Use the following relation:

\omega = \frac{v}{r}

L_b = MR^2(\frac{v}{R}) = MRv

Plug in the given values:

L_b = (20)(3)(5) = 300 kgm^2/s

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I = MR^2\\I = 20(3^2) = 180 kgm^2

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600(0) + 300 = \omega_f(180 + 600)\\\\300 = 780\omega_f\\\\\omega = \boxed{0.38 rad/sec}

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