To determine the amount of 6.0 M H2SO4 needed for the preparation, equate the number of moles of the 6.0 M and 2.5 M H2SO4 solution. This is done as follows
M1 x V1 = M2 x V2
Substituting the known variables,
(6.0 M) x V1 = (2.5 M) x (4.8 L)
Solving for V1 gives an answer of V1 = 2 L. Thus, to prepare the needed solution, dilute 2 L of 6.0 M H2SO4 solution with water until the volume reach 4.8 L.
<h3>
Answer:</h3>
79.8 ml
<h3>
Explanation:</h3>
Boyle's law describes the relationship between pressure and volume when the temperature is constant. For this question, I will be rounding to significant figures.
Boyle's Formula
When describing the relationship between pressure and volume, the formula
. In this formula,
is the initial pressure and volume. On the other side,
is final pressure and volume. So, to find a missing variable you must plug in the values you are given.
Final Volume
Remember when solving this question to remain constant in your units. When we plug in the values we know we are given:
Now, we can multiply the left side
Finally, we can divide by 385 to isolate the final volume
This gives the final volume of 79.8mL.
<span>d. the amount heat produced in the reaction
Another table of values for Energy Content is required. So option D is not possible to calculate.</span>
= 30802.53 im pretty sure if im wrong let me know its the best i can do :/