Question

What is the concentration of O2(g), in parts per million, in a solution that contains 0.008 gram of O2(g) dissolved in 1000. grams of H2O(2)?
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1

0.8 ppm

8 ppm

80 ppm

800 ppm

Answer 1

Answer : The concentration of $O_2$ (g) in parts per million is, 8 ppm

Explanation : Given,

Mass of oxygen gas (solute) = 0.008 g

Mass of water (solvent) = 1000 g

First we have to calculate the mass of solution.

Mass of solution = Mass of solute + Mass of solvent = 0.008 + 1000 = 1000.008 g

Now we have to calculate the concentration of  $O_2$ (g) in parts per million.

ppm : It is defined as the mass of solute present in one million $(10^6)$ parts by mass of the solution.

$ppm=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^6$

Now put all the given values in this expression, we get

$ppm=\frac{0.008g}{1000.008g}\times 10^6=7.99=8ppm$

Therefore, the concentration of $O_2$ (g) in parts per million is, 8 ppm