1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Phantasy [73]
3 years ago
6

Chemical formula for ethene

Chemistry
1 answer:
Yakvenalex [24]3 years ago
8 0
I believe that the answer is C2H4 :)
You might be interested in
What is the formula mass of mgcl2
NeX [460]

Answer:

The formula mass of MgCl2 is 95, 3 grams (the weight of 1 mol of compound)

Explanation:

We calculate the weight of 1 mol of MgCl2:

Weight of 1mol of MgCl2=atomic  weight Mg + (atomic weight Cl)x  2=

24, 3 grams + 2 x 35, 5 grams = 95, 3 grams/mol MgCl2

8 0
3 years ago
Animals can change the energy in food into energy the animals can use. What type of energy is in the food before the animals cha
SVEN [57.7K]

D. Light energy is the right answer

7 0
3 years ago
given the mass lost during the reaction when the alka seltzer is the limiting reagent and that the molar mass of carbon dioxide
Vadim26 [7]
Alka-seltzer is an effervescent antacid which neutralizes the acid of the stomach by generating CO2. The chemical formula of alka-seltzer is C16H17NaO14. In this case, if we are given the mass of the antacid used, then by stoichiometry, mass alka-seltzer * (1/ molar mass of alk-selz) * (1 mol Co2 / 1 mol alk-seltz) * (44 g/molCo2). That is how you get the mass of Co2 produced.
5 0
3 years ago
How much heat is required to melt 20 g of gold at 1064.18 °C with a heat of fusion of 64 J/g *
andrew-mc [135]

Answer:

1280J are required.

Explanation:

Heat of fusion is defined as the amount of heat required to change its state from liquid to solid at its melting point at constant pressure.

As heat of fusion of gold is 64J/g, there are required 64J to melt 1g of gold at its melting point. The energy required to melt 20g is:

20g * (64J/g) =

1280J are required

6 0
2 years ago
For the reaction A+B+C→D+E, the initial reaction rate was measured for various initial concentrations of reactants. The followin
erastovalidia [21]

Answer : The initial rate for a reaction will be 3.4\times 10^{-3}Ms^{-1}

Explanation :

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

A+B+C\rightarrow D+E

Rate law expression for the reaction:

\text{Rate}=k[A]^a[B]^b[C]^c

where,

a = order with respect to A

b = order with respect to B

c = order with respect to C

Expression for rate law for first observation:

6.0\times 10^{-5}=k(0.20)^a(0.20)^b(0.20)^c ....(1)

Expression for rate law for second observation:

1.8\times 10^{-4}=k(0.20)^a(0.20)^b(0.60)^c ....(2)

Expression for rate law for third observation:

2.4\times 10^{-4}=k(0.40)^a(0.20)^b(0.20)^c ....(3)

Expression for rate law for fourth observation:

2.4\times 10^{-4}=k(0.40)^a(0.40)^b(0.20)^c ....(4)

Dividing 1 from 2, we get:

\frac{1.8\times 10^{-4}}{6.0\times 10^{-5}}=\frac{k(0.20)^a(0.20)^b(0.60)^c}{k(0.20)^a(0.20)^b(0.20)^c}\\\\3=3^c\\c=1

Dividing 1 from 3, we get:

\frac{2.4\times 10^{-4}}{6.0\times 10^{-5}}=\frac{k(0.40)^a(0.20)^b(0.20)^c}{k(0.20)^a(0.20)^b(0.20)^c}\\\\4=2^a\\a=2

Dividing 3 from 4, we get:

\frac{2.4\times 10^{-4}}{2.4\times 10^{-4}}=\frac{k(0.40)^a(0.40)^b(0.20)^c}{k(0.40)^a(0.20)^b(0.20)^c}\\\\1=2^b\\b=0

Thus, the rate law becomes:

\text{Rate}=k[A]^2[B]^0[C]^1

Now, calculating the value of 'k' by using any expression.

Putting values in equation 1, we get:

6.0\times 10^{-5}=k(0.20)^2(0.20)^0(0.20)^1

k=7.5\times 10^{-3}M^{-2}s^{-1}

Now we have to calculate the initial rate for a reaction that starts with 0.75 M of reagent A and 0.90 M of reagents B and C.

\text{Rate}=k[A]^2[B]^0[C]^1

\text{Rate}=(7.5\times 10^{-3})\times (0.75)^2(0.90)^0(0.90)^1

\text{Rate}=3.4\times 10^{-3}Ms^{-1}

Therefore, the initial rate for a reaction will be 3.4\times 10^{-3}Ms^{-1}

8 0
2 years ago
Other questions:
  • Help me solve the question please I'm a struggling college student
    12·2 answers
  • How many Milligrams of potassium chloride KCl are required to make a 15 mL of a 1.20 M solution?​
    6·1 answer
  • How did Albert Einstein explain the photoelectric effect?
    7·2 answers
  • Which is a good example of a contact force? A. protons in the nucleus of an atom B. a ball falling down after it's thrown up int
    6·1 answer
  • I am accessible in most locations on Earth, but certain areas have much more of me. I am perpetually renewed and cause little or
    6·2 answers
  • 22 Directions: Select the correct food web. In Ottawalley National Park, grass is abundant. Gazelles spend most of the day feedi
    11·2 answers
  • 65 g of NaOH is dissolved to make 500 mL of solution. Find moles of NaPH and Molarity of solution.
    10·1 answer
  • 4.) The temperature of solid silver increases from 30C to 40C by the addition of 117.5
    5·1 answer
  • ​Bbsbsjsjsjwjwjwjwjehhehehe
    9·1 answer
  • I Need Help on these science questions
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!