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2 years ago

10

The gas law for a fixed mass m of an ideal gas at absolute temperature T, pressure P, and volume V is PV=mRT, where R is the gas

constant. Find the partial derivatives

1 answer:

Solnce55 [7]2 years ago

4 0

Answer:

the equation is

P*V = mRT.

The partial derivatives are:

For P = mRT/V.

$dP/dV = -\frac{mRT}{V^2}$

$dP/dT = \frac{mR}{V}$

now, if we take:

V = mRT/P

$dV/dT = \frac{mR}{P}$

$dV/dP = -\frac{mRT}{P^2} = (dP/dV)^{-1} = -\frac{V^2}{mRT}$

If we take T = PV/mR

$dT/dP = \frac{V}{mR} = (dP/dT)^{-1}$

$dT/dV = \frac{P}{mR} = (dV/dT)^{-1}$

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3 years ago

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Dmitriy789 [7]

Answer:

d = 2.54 [m]

Explanation:

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where:

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where:

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But the friction force is equal to the product of the normal force (body weight) by the coefficient of friction.

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3 years ago

Vector A has a magnitude of 16 m and makes an angle of 44° with the positive x axis. Vector B also has a magnitude of 13 m and i

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Answer with explanation:

The given vectors in are reduced to their componednt form as shown

For vector A it can be written as

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Similarly vector B can be written as

$\overrightarrow{v}_{b}=-13\widehat{i}$

Hence The sum and difference is calculated as

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The direction is given by

$\theta =tan^{-1}\frac{r_{y}}{r_{x}}\\\\\theta =tan^{-1}\frac{11.11}{-1.49}=97.64^{o}$ with positive x axis.

Similarly

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GenaCL600 [577]

Complete Question

For each of the following scenarios, describe the force providing the centripetal force for the motion:

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d. a rock swinging on a string

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Answer:

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Considering b

The force providing the centripetal force is the force experienced by the boys hand on the pole

Considering c

The force providing the centripetal force is the normal from the bench due to the boys weight

Considering d

The force providing the centripetal force is the tension on the string

Considering e

The force providing the centripetal force is the force of gravity between the earth and the sun

Explanation:

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3 years ago