The centripetal acceleration is 
Explanation:
The centripetal acceleration for an object in circular motion is given by

where
v is the linear speed
r is the radius of the circle
The body in the problem cover half of revolution in
t = 10 s
And the corresponding linear distance covered is
L = 10 m
which corresponds to half of the circumference, so

From this equation we find the radius of the circle:
[m]
While the linear speed is:

Therefore, the centripetal acceleration is

Learn more about circular motion:
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Answer:
A) True, B) False, C) False and D) false
Explanation:
Let's solve the problem using the law of conservation of energy to know if the statements are true or false
Let's look for mechanical energy
Initial
Emo = Ke = ½ k Dx2
Final
Em1= ½ m v12
Emo = Em1
½ k Δx2 = ½ m v₁²
v₁² = k / m Δx²
v₁ = √ k/m Δx
Now let's calculate the speed when it falls
Vfy² = Voy² - 2gy
Vfy² = - 2gy
Vf² = v₁² + vfy²
A) True v₁ = A Δx
.B) False. As there is no rubbing the mechanical energy conserves
.C) False the velocity is proportional to the square root of the height
v2y = v2 √2
. D) false promotional compression speed
Answer:
Kinetic Energy = 1/2mv^2
Kinetic Energy = 1/2(150 kg)(20 m/s)^2
Kinetic Energy = 75 kg(400 m/s)
Kinetic Energy = 30000 J
Let me know if this helps!
Their relative speed is the sum of 60 and 40 or 100km/hr. They will travel the 150km in 1.5 hrs.<span>When two object approach each other, the closing speed is just the sum of the speeds, therefore, the closing speed is your case is 100kph. </span>
<span>Just take the distance of 150 km and divide by 100 to get 1.5 hours </span>
<span>checking: </span>
<span>the car going 60 will have traveled 60*1.5 = 90 km </span>
<span>the car going 40 will have traveled 40*1.5 = 60 km </span>
<span>the sum of the distances = 90+60 = 1.5 hours </span>
<span>So they will meet in 1.5 hours.</span>