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irina [24]
3 years ago
10

The gas law for a fixed mass m of an ideal gas at absolute temperature T, pressure P, and volume V is PV=mRT, where R is the gas

constant. Find the partial derivatives
Physics
1 answer:
Solnce55 [7]3 years ago
4 0

Answer:

the equation is

P*V = mRT.

The partial derivatives are:

For P = mRT/V.

dP/dV = -\frac{mRT}{V^2}

dP/dT = \frac{mR}{V}

now, if we take:

V = mRT/P

dV/dT = \frac{mR}{P}

dV/dP = -\frac{mRT}{P^2} = (dP/dV)^{-1} = -\frac{V^2}{mRT}

If we take T = PV/mR

dT/dP = \frac{V}{mR} = (dP/dT)^{-1}

dT/dV = \frac{P}{mR} = (dV/dT)^{-1}

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A body moves in circle cover half of revolution in 10 sec its linear distance became 10m along circumference of circle than its
stiks02 [169]

The centripetal acceleration is 0.63 m/s^2

Explanation:

The centripetal acceleration for an object in circular motion is given by

a=\frac{v^2}{r}

where

v is the linear speed

r is the radius of the circle

The body in the problem cover half of revolution in

t = 10 s

And the corresponding linear distance covered is

L = 10 m

which corresponds to half of the circumference, so

L=2\pi r

From this equation we find the radius of the circle:

r=\frac{L}{2\pi}=\frac{10}{2\pi}=1.59 m [m]

While the linear speed is:

v=\frac{L}{t}=\frac{10}{10}=1 m/s

Therefore, the centripetal acceleration is

a=\frac{1^2}{1.59}=0.63 m/s^2

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

4 0
3 years ago
A block of mass m is compressed against a spring (spring constant kk) on a horizontal frictionless surface. The block is then re
Nimfa-mama [501]

Answer:

A) True, B) False, C) False  and  D) false

Explanation:

Let's solve the problem using the law of conservation of energy to know if the statements are true or false

Let's look for mechanical energy

Initial

     Emo = Ke = ½ k Dx2

Final

     Em1= ½ m v12

     Emo = Em1

     ½ k Δx2 = ½ m v₁²

    v₁² = k / m Δx²

    v₁ = √ k/m   Δx

Now let's calculate the speed when it falls

   Vfy² = Voy² - 2gy

   Vfy² = - 2gy

   Vf² = v₁² + vfy²

A) True     v₁ = A Δx

.B) False. As there is no rubbing the mechanical energy conserves

.C) False the velocity is proportional to the square root of the height

     v2y = v2 √2

. D) false promotional compression speed

3 0
3 years ago
What is the kinetic energy of a go kart with a mass of 150 kilograms and a speed of 20 m/s?
lyudmila [28]

Answer:

Kinetic Energy = 1/2mv^2

Kinetic Energy = 1/2(150 kg)(20 m/s)^2

Kinetic Energy = 75 kg(400 m/s)

Kinetic Energy = 30000 J

Let me know if this helps!

6 0
3 years ago
Two automobiles are 150 kilometers apart and traveling toward each other. One automobile is moving at 60 km/h and the other is m
faltersainse [42]
Their relative speed is the sum of 60 and 40 or 100km/hr. They will travel the 150km in 1.5 hrs.<span>When two object approach each other, the closing speed is just the sum of the speeds, therefore, the closing speed is your case is 100kph. </span>

<span>Just take the distance of 150 km and divide by 100 to get 1.5 hours </span>

<span>checking: </span>

<span>the car going 60 will have traveled 60*1.5 = 90 km </span>
<span>the car going 40 will have traveled 40*1.5 = 60 km </span>

<span>the sum of the distances = 90+60 = 1.5 hours </span>

<span>So they will meet in 1.5 hours.</span>
8 0
3 years ago
Read 2 more answers
When experimenting with the photoelectric effect, what factor of light affected the kinetic energy of the electrons emitted from
Shtirlitz [24]

Answer:

c

Explanation:

intensity of light in the

5 0
3 years ago
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