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irina [24]
3 years ago
10

The gas law for a fixed mass m of an ideal gas at absolute temperature T, pressure P, and volume V is PV=mRT, where R is the gas

constant. Find the partial derivatives
Physics
1 answer:
Solnce55 [7]3 years ago
4 0

Answer:

the equation is

P*V = mRT.

The partial derivatives are:

For P = mRT/V.

dP/dV = -\frac{mRT}{V^2}

dP/dT = \frac{mR}{V}

now, if we take:

V = mRT/P

dV/dT = \frac{mR}{P}

dV/dP = -\frac{mRT}{P^2} = (dP/dV)^{-1} = -\frac{V^2}{mRT}

If we take T = PV/mR

dT/dP = \frac{V}{mR} = (dP/dT)^{-1}

dT/dV = \frac{P}{mR} = (dV/dT)^{-1}

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A tank contains gas at 13.0°C pressurized to 10.0 atm. The temperature of the gas is increased to 95.0°C, and half the gas is re
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Answer:

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Explanation:

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We need to calculate the pressure of the remaining gas

Using equation of ideal gas

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For a gas

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V = volume

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Put the value in the equation

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Then,

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Divided equation (I) by equation (II)

\dfrac{P_{1}V}{P_{2}V}=\dfrac{nRT_{1}}{\dfrac{n}{2}RT_{2}}

\dfrac{10\times V}{P_{2}V}=\dfrac{nR\times286}{\dfrac{n}{2}R368}

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