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BartSMP [9]
3 years ago
8

"Which of the following processes takes place in the cytosol of a eukaryotic cell?" View Available Hint(s) Which of the followin

g processes takes place in the cytosol of a eukaryotic cell? acetyl CoA formation citric acid cycle glycolysis electron transport chain ATP production by ATP synthase
Chemistry
1 answer:
Rufina [12.5K]3 years ago
6 0

Answer:

The correct answer is Glycolysis.

Explanation:

Glycolysis is a catabolic process that deals with the breakdown of glucose by 10 enzyme catalyzed steps to generate the end product pyruvate.

      Glycolysis take place in the cytosol of an eukaryotic cell because the concentration of glucose and enzymes that catalyzes the break down of glucose remain significantly high in the cytosol.

         

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What is the molecular formula of first 20 elements​
attashe74 [19]

Answer:

H

He

Li

Be

B

C

N

O

F

Ne

Na

Mg

Al

Si

P

S

Cl

Ar

K

Ca

3 0
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Can someone please help me
Lilit [14]
It is A. Barium

Explanation: I did that already
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How many “p” orbital in principal energy level below?​
marshall27 [118]

Answer:

Each principal energy level above the first contains one s orbital and three p orbitals. A set of three p orbitals, called the p sublevel, can hold a maximum of six electrons. Therefore, the second level can contain a maximum of eight electrons - that is, two in the s orbital and 6 in the three p orbitals.

Explanation:

5 0
3 years ago
Question 2
QveST [7]
Metals only and ionic
3 0
3 years ago
Read 2 more answers
A chemistry student weighs out of sulfurous acid , a diprotic acid, into a volumetric flask and dilutes to the mark with distill
nadezda [96]

The question is incomplete, here is the complete question:

A chemistry student weighs out 0.104 g of sulfurous acid, a diprotic acid, into a 250.0 mL volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.0700 M NaOH solution. Calculate the volume of NaOH solution the student will need to add to reach the final equivalence point. Be sure your answer has the correct number of significant digits.

<u>Answer:</u> The volume of NaOH needed is 36.2 mL

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Given mass of sulfurous acid = 0.104 g

Molar mass of sulfurous acid = 82 g/mol

Volume of solution = 250 mL

Putting values in above equation, we get:

\text{Molarity of sulfurous acid}=\frac{0.104\times 1000}{82\times 250}\\\\\text{Molarity of sulfurous acid}=5.07\times 10^{-3}M

To calculate the volume of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=5.07\times 10^{-3}M\\V_1=250mL\\n_2=1\\M_2=0.0700M\\V_2=?mL

Putting values in above equation, we get:

2\times 5.07\times 10^{-3}\times 250.0=1\times 0.0700\times V_2\\\\V_2=\frac{2\times 5.07\times 10^{-3}\times 250}{1\times 0.0700}=36.2mL

Hence, the volume of NaOH needed is 36.2 mL

5 0
3 years ago
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