Answer: The volume is decreasing at a rate of 80 cm3/min
Explanation: Please see the attachments below
which best describes how magnesium (mg) and oxygen (o) bond? they form an ionic bond by exchanging two electrons. they form an i
2 answers:
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The answer is 41.25 mph.
The average speed (v) can be expressed as:
v = D/T
where
D is total distance: D = d1 + d2 + d3 + d4
T is total time: T = t1 + t2 + t3 + t4
Now let's calculate distances using the formula: d = v * t:
d1 = v1 * t1 = 20.0 * 0.500 = 10 mi
d2 = v2 * t2 = 40.0 * 1.00 = 40 mi
d3 = v3 * t3 = 30.0 * 0.500 = 15 mi
d4 = v4 * t4 = 50.0 * 2.00 = 100 mi
Thus, the average speed is:
The average speed (v) can be expressed as:
v = D/T
where
D is total distance: D = d1 + d2 + d3 + d4
T is total time: T = t1 + t2 + t3 + t4
Now let's calculate distances using the formula: d = v * t:
d1 = v1 * t1 = 20.0 * 0.500 = 10 mi
d2 = v2 * t2 = 40.0 * 1.00 = 40 mi
d3 = v3 * t3 = 30.0 * 0.500 = 15 mi
d4 = v4 * t4 = 50.0 * 2.00 = 100 mi
Thus, the average speed is:
Answer:
The magnitude of the force on positive charges will be and the magnitude of the force on the negative charge is
.
Explanation:
Given:
The value of the charges, .
The length of each side of the triangle, .
Consider a equilateral triangle , as shown in the figure. Let two point charges of magnitude
are situated at points
and
and another point charge
is situated at point
.
The value of the force on the charge at point due to charge at point
is given by
The value of the force on the charge at point due to charge at point
is given by
The net resultant force on the charge at point is given by
The value of the force on the charge at point due to charge at point
is given by
The value of the force on the charge at point due to charge at point
is given by
The net resultant force on the charge at point is given by
The value of the force on the charge at point due to charge at point
is given by
The value of the force on the charge at point due to charge at point
is given by
The net resultant force on the charge at point is given by
Substitute for
,
for
and
for
in equation (1), we have
Substitute for
,
for
and
for
in equation (2), we have
Substitute for
,
for
and
for
in equation (3), we have
