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Lisa [10]
3 years ago
15

In this task, you have worked with numeric fractions and algebraic fractions (rational expressions). Describe how operations on

fractions with numbers are similar to, and different from, operations on fractions with variables.
Mathematics
1 answer:
MAXImum [283]3 years ago
4 0
When you use variables, you can end up with the denominator being zero which is undefined
You might be interested in
A rectangular patio has a length of 12 1/2 feet and an area of 103 1/8 square feet. What is the width of the patio?
Rina8888 [55]
Length of the rectangular patio = 12 1/2 feet
                                                  = 25/2 feet
Area of the rectangular patio = 103 1/8 square feet
                                               = 825/8 square feet
Let us assume the width of the rectangular patio = x feet
 Then
Area of the rectangular patio = Length * Width
825/8 = (25/2) * x
25x/2 = 825/8
25x = (825 * 2)/8 feet
25x = 825/4 feet
x = 825/(4 * 25) feet
   = 33/4 feet
   = 8 1/4 feet
So the width of the rectangular patio is 8 1/4 feet. I hope the procedure is clear enough for you to understand.
6 0
3 years ago
2/4 + 3/9 in Modeling Fractions?
horrorfan [7]

Answer: 13/12

Step-by-step explanation:

Reduce the fraction 3/9 to the lowest terms by extracting and canceling out 3.

The least common multiple of 4 and 3 is 12. Convert 3/4 and 1/3 to fractions with denominator 12.

Since 9/12 and 4/12 have the same denominator, add them by adding their numerators.

Add 9 and 4 to get 13.

5 0
2 years ago
PLD HELP ME I WILL FAIL PLSx​
elena55 [62]

Answer:

19.4236 is your answer

Step-by-step explanation:

8 0
3 years ago
What are the solutions of the equation (2x + 3)2 + 8(2x + 3) + 11 = 0
Tom [10]

Answer:

x=\frac{-7-\sqrt{5}}{2} or x=\frac{-7+ \sqrt{5}}{2}

Step-by-step explanation:

The given equation is

(2x+3)^2+8(2x+3)+11=0

Let us treat this as a quadratic equation in (2x+3).

where a=1,b=8,c=11

The solution is given by the quadratic formula;

(2x+3)=\frac{-b\pm \sqrt{b^2-4ac} }{2a}

We substitute these values into the formula to obtain;

(2x+3)=\frac{-8\pm \sqrt{8^2-4(1)(11)} }{2(1)}

(2x+3)=\frac{-8\pm \sqrt{64-44} }{2}

(2x+3)=\frac{-8\pm \sqrt{20} }{2}

(2x+3)=\frac{-8\pm2\sqrt{5} }{2}

(2x+3)=-4\pm \sqrt{5}

(2x+3)=-4-\sqrt{5} or (2x+3)=-4+ \sqrt{5}

2x=-3-4-\sqrt{5} or 2x=-3-4+ \sqrt{5}

2x=-7-\sqrt{5} or 2x=-7+ \sqrt{5}

x=\frac{-7-\sqrt{5}}{2} or x=\frac{-7+ \sqrt{5}}{2}

5 0
3 years ago
Find the volume of the composite solid. Round your answer to the nearest tenth.
Damm [24]

Answer:

402.12 + 804.24 = 1206.36

8 0
2 years ago
Read 2 more answers
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