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Butoxors [25]
3 years ago
9

Describe the differences in the atomic structures of a hydrogen atom and a helium atom.

Physics
2 answers:
pentagon [3]3 years ago
7 0

A helium atom would never explode and is non-reactive, whereas a hydrogen atom is.

A helium atom is not flammable because it is one of the Inert Gasses; In contrast, Hydrogen is flammable. It reacts explosively with Oxygen


I think I am correct, but comment if I'm wrong :-)

AnnyKZ [126]3 years ago
6 0

The other answer here says nothing about the structures
of a Hydrogen atom or a Helium atom.


In "classical terms" ... where we picture an atom something
like a tiny tiny solar system ...

-- The nucleus of a Hydrogen atom is a single proton,
whereas the nucleus of a Helium atom is a tightly bound
bundle of four particles ... 2 protons and 2 neutrons. 
This also means that every atom of Helium has 4 times
the mass of a Hydrogen atom.

-- In addition to the atomic nucleus, one electrically-neutral
atom of Hydrogen has an electron associated with the nucleus
and at some distance from it, whereas an electrically-neutral atom
of Helium has two electrons.

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What kind of force can be created with an electrical current?
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Answer:

magnatic force can be created

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How are the fiducial points of the Celsius and Fahrenheit scales similar?
taurus [48]
The fiducial points of the Celsius<span> and the </span>Fahrenheit<span> temperature </span>scales<span> are the boiling and freezing </span>points<span> of pure water at 1 atm of pressure.

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7 0
3 years ago
A car travels 40 miles in 30 minutes.
lukranit [14]

Answer:

(a)Average velocity ,v =128.74 Km/hr

(b)Kinetic Energy , K=958546.875 Joule

(c)Distance, s=268.8m

(d)Acceleration, a= - 2.38 m/s^2

<u>Explanation</u>:

<u>Given</u>:

Distance travelled = 40 miles

Time taken = 30 minutes.

(A) The average velocity in kilometres/hour

Converting 40 miles into km ,

we know that,

1 mile = 1.60934

40 miles =  40 x 1.60934

so 40 miles  =  64.3738 Km

similarly converting 30 minutes into hours

1 minute = \frac{1}{60}hours

30 minute = \frac{30}{60}hours

30 minute = \frac{1}{2}hours

Now

Average velocity = \frac{Speed}{time}

Substituting Values,

Average velocity = \frac{64.3738}{\frac[1}{2}}

Average velocity = 64.3738 \times 2

Average velocity =128.74 Km/hr

(B) If the car weighs 1.5 tons, what is its If the car weighs 1.5 tons, what is its kinetic energy in joules (Note: you will need to convert your velocity to m/s)? in joules (Note: you will need to convert your velocity to m/s)?

Converting 1.5 tons into kg we get

1 ton = 1000 kg

so 1.5 ton =1500 kg

converting  velocity to m/s

128.74  \times \frac{5}{18}

=>35.75 m/s----------------------------------------------------------(1)

kinetic energy  K= \frac{1}{2}mv^2

Substituting the values,

K= \frac{1}{2}1500(35.75)^2

K= \frac{1}{2}1500(1278.06)

K= \frac{1500 \times (1278.06)}{2}

K= \frac{1917093.75}{2}

K=958546.875 Joule---------------------------------------------(2)

(c)When the driver applies the brake, it takes 15 seconds to stop. How far does the car travel (in meters) while stopping

Lets use Distance formula,

S= ut+\frac{1}{2}at^2

Substituting the known values,

s= ut+\frac{1}{2}at^2

s= (37.75)(15)+\frac{1}{2}a(15)^2

s=566.25+\frac{1}{2}a(225)

s=566.25+\frac{(225a)}{2}-------------------------------------(3)

(D) What is the average acceleration of the car (in m/s2) during braking?

Using the formula

v=u +at

re arranging the formula we get,

a = \frac{v - u}{t}

Substituting the values

a = \frac{0 - 35.75}{15}

a = \frac{- 35.75}{15}

a= - 2.38 m/s^2----------------------------------------(4)

Now substituting 4 in 3 we get

s=566.25+\frac{(225( - 2.38)}{2}

s=566.25+\frac{-535.5}{2}

s=536.25-267.75

s=268.8m--------------------------------------------------------------(5)

4 0
3 years ago
Please need help with this
PtichkaEL [24]
Through is the answer to your question
3 0
3 years ago
Read 2 more answers
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