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Butoxors [25]
3 years ago
9

Describe the differences in the atomic structures of a hydrogen atom and a helium atom.

Physics
2 answers:
pentagon [3]3 years ago
7 0

A helium atom would never explode and is non-reactive, whereas a hydrogen atom is.

A helium atom is not flammable because it is one of the Inert Gasses; In contrast, Hydrogen is flammable. It reacts explosively with Oxygen


I think I am correct, but comment if I'm wrong :-)

AnnyKZ [126]3 years ago
6 0

The other answer here says nothing about the structures
of a Hydrogen atom or a Helium atom.


In "classical terms" ... where we picture an atom something
like a tiny tiny solar system ...

-- The nucleus of a Hydrogen atom is a single proton,
whereas the nucleus of a Helium atom is a tightly bound
bundle of four particles ... 2 protons and 2 neutrons. 
This also means that every atom of Helium has 4 times
the mass of a Hydrogen atom.

-- In addition to the atomic nucleus, one electrically-neutral
atom of Hydrogen has an electron associated with the nucleus
and at some distance from it, whereas an electrically-neutral atom
of Helium has two electrons.

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While doing a lab, a student found the density of a piece of pure aluminum to be 2.85 g/cm3. The accepted value for the density
bezimeni [28]
The equation for percent error is

% Error = 100*|Experimental-Theoretical|/Theoretical

Our experimental is 2.85g/cm^3 and the accepted is 2.7g/cm^3

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3 0
3 years ago
What statement about the greenhouse effect is not true?
Nimfa-mama [501]

The so-called greenhouse effect is observed only in houses painted green, and even there, only between the hours of 2PM - 4PM local time on Thursday afternoon.

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3 years ago
A neutron consists of one "up" quark of charge +2e/3 and two "down" quarks each having charge -e/3. If we assume that the down q
Anon25 [30]

Answer:

The magnitude of the electrostatic force is 120.85 N

Explanation:

We can use Coulomb's law to find the electrostatic force between the down quarks.

In scalar form, Coulomb's law states that for charges q_1 and q_2 separated by a distance d, the magnitude of the electrostatic force F between them is:

F = k \frac{|q_1q_2|}{d^2}

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Taking the values:

d = 4.6 \ 10^{-15} m

q_1 = q_2 = - \frac{e}{3} = - \frac{1.6 \ 10^{-19} \ C}{3}

and knowing the value of the Coulomb's constant:

k = 8.99 \ 10 ^{9} \frac{N m^2}{C^2}

Taking all this in consideration:

F = 8.99 \ 10 ^{9} \frac{N m^2}{C^2} \frac{ (- \frac{1.6 \ 10^{-19} \ C}{3} ) ^2}{(4.6 \ 10^{-15} m)^2}

F = 120.85  \ N

8 0
3 years ago
A gyroscope flywheel of radius 3.25 cm is accelerated from rest at 11.6 rad/s2 until its angular speed is 1820 rev/min. (a) What
kati45 [8]

Explanation:

The given data is as follows.

           radius (r) = 3.25 cm,    \alpha = 11.6 rad/s^{2}

Now, we will calculate the tangential acceleration as follows.

          a_{tangential} = \alpha \times r

Putting the given values into the above formula as follows.

         a_{tangential} = \alpha \times r

                      = 11.6 rad/s^{2} \times 3.25 cm

                      = 37.7 rad cm/s^{2}

Thus, we can conclude that the tangential acceleration of a point on the rim of the flywheel during this spin-up process is 37.7 rad cm/s^{2}.

6 0
3 years ago
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Komok [63]

25km / 4hr = <em>6.25 km/hr east</em>

6 0
3 years ago
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