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Vanyuwa [196]
4 years ago
11

Take my points because I can am making another account

Engineering
2 answers:
ValentinkaMS [17]4 years ago
7 0

Answer:

Match the following.

1.

a graph that uses a rectangle and line segments to show the clustering of a set of data

2.

the difference between the first and the third quartiles

3.

the smallest data point in a set

4.

median of the lower half of a set of data

5.

the middle value of a set of data arranged in numerical order

6.

division of data into four equal parts

7.

the highest data point in a set of data

8.

median of the upper half of a set of data

box-and-whisker plot

interquartile range

median

lower quartile

upper extreme

upper quartile

quartile

lower extremeMatch the following.

1.

a graph that uses a rectangle and line segments to show the clustering of a set of data

2.

the difference between the first and the third quartiles

3.

the smallest data point in a set

4.

median of the lower half of a set of data

5.

the middle value of a set of data arranged in numerical order

6.

division of data into four equal parts

7.

the highest data point in a set of data

8.

median of the upper half of a set of data

box-and-whisker plot

interquartile range

median

lower quartile

upper extreme

upper quartile

quartile

lower extremeMatch the following.

1.

a graph that uses a rectangle and line segments to show the clustering of a set of data

2.

the difference between the first and the third quartiles

3.

the smallest data point in a set

4.

median of the lower half of a set of data

5.

the middle value of a set of data arranged in numerical order

6.

division of data into four equal parts

7.

the highest data point in a set of data

8.

median of the upper half of a set of data

box-and-whisker plot

interquartile range

median

lower quartile

upper extreme

upper quartile

quartile

lower extremeMatch the following.

1.

a graph that uses a rectangle and line segments to show the clustering of a set of data

2.

the difference between the first and the third quartiles

3.

the smallest data point in a set

4.

median of the lower half of a set of data

5.

the middle value of a set of data arranged in numerical order

6.

division of data into four equal parts

7.

the highest data point in a set of data

8.

median of the upper half of a set of data

box-and-whisker plot

interquartile range

median

lower quartile

upper extreme

upper quartile

quartile

lower extremeMatch the following.

1.

a graph that uses a rectangle and line segments to show the clustering of a set of data

2.

the difference between the first and the third quartiles

3.

the smallest data point in a set

4.

median of the lower half of a set of data

5.

the middle value of a set of data arranged in numerical order

6.

division of data into four equal parts

7.

the highest data point in a set of data

8.

median of the upper half of a set of data

box-and-whisker plot

interquartile range

median

lower quartile

upper extreme

upper quartile

quartile

lower extreme

Explanation:

UkoKoshka [18]4 years ago
4 0

Answer:

thank you so muchhhhhhh

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Maximum iorsional shear siress.? Select one: a)- occurs at the center of a shaft. b)- occurs at the outer surface of a shaft c)-
pickupchik [31]

Answer:

b). Occurs at the outer surface of the shaft

Explanation:

We know from shear stress and torque relationship, we know that

\frac{T}{J}= \frac{\tau }{r}

where, T = torque

            J = polar moment of inertia of shaft

            τ = torsional shear stress

             r = raduis of the shaft

Therefore from the above relation we see that

            \tau = \frac{T.r}{J}

Thus torsional shear stress, τ is directly proportional to the radius,r of the shaft.

When r= 0, then τ = 0

and when r = R , τ is maximum

Thus, torsional shear stress is maximum at the outer surface of the shaft.

4 0
4 years ago
You were hoping to receive a scholarship for volleyball and are entering your personal information and statistics on a secure we
kozerog [31]
I think it is fair to say 5 and 3/4 inches.
6 0
3 years ago
Read 2 more answers
A non-licensed person may be the SOLE owner of a civil, electrical, or mechanical engineering business under which of the follow
kotegsom [21]

Answer:

(d) None. No provisions exist.

Explanation:

B&P Code § 6738 prohibits a non-licensed person from being the sole proprietor of an engineering business. The non-licensed can be a partner in an engineering business that offers civil, electrical, or mechanical services. It is mandatory that at least one licensed engineer must be a co-owner of the business.

5 0
3 years ago
A 0.2-m^3 rigid tank equipped with a pressure regulator contains steam at 2MPa and 320C. The steam in the tank is now heated. Th
prohojiy [21]

Answer:

Q=486.49 KJ/kg

Explanation:

Given that

V= 0.2 m³

At initial condition

P= 2 MPa

T=320 °C

Final condition

P= 2 MPa

T=540°C

From steam table

At P= 2 MPa and T=320 °C

h₁=3070.15 KJ/kg

At P= 2 MPa and T=540°C

h₂=3556.64  KJ/kg

So the heat transfer ,Q=h₂ - h₁

Q= 3556.64 - 3070.15  KJ/kg

Q=486.49 KJ/kg

7 0
3 years ago
Use phasor techniques to determine the impedance seen by the source given that R = 4 Ω, C = 12 μF, L = 6 mH and ω = 2000 rad/sec
Zielflug [23.3K]

Answer:

Z = 29.938Ω ∠22.04°

I = 2.494A

Explanation:

Impedance Z is defined as the total opposition to the flow of current in an AC circuit. In an R-L-C AC circuit, Impedance is expressed as shown:

Z² = R²+(Xl-Xc)²

Z = √R²+(Xl-Xc)²

R is the resistance = 4Ω

Xl is the inductive reactance = ωL

Xc is the capacitive reactance =

1/ωc

Given C = 12 μF, L = 6 mH and ω = 2000 rad/sec

Xl = 2000×6×10^-3

Xl = 12Ω

Xc = 1/2000×12×10^-6

Xc = 1/24000×10^-6

Xc = 1/0.024

Xc = 41.67Ω

Z = √4²+(12-41.67)²

Z = √16+880.31

Z = √896.31

Z = 29.938Ω (to 3dp)

θ = tan^-1(Xl-Xc)/R

θ = tan^-1(12-41.67)/12

θ = tan^-1(-29.67)/12

θ = tan^-1 -2.47

θ = -67.96°

θ = 90-67.96

θ = 22.04° (to 2dp)

To determine the current, we will use the relationship

V = IZ

I =V/Z

Given V = 12V

I = 29.93/12

I = 2.494A (3dp)

7 0
3 years ago
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