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3 years ago

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A proton, moving in a uniform magnetic field, moves in a circle perpendicular to the field lines and takes time T for each circl

e. If the proton's speed tripled, what would now be its time to go around each circle?
A- 3T
B- T
C- T/3
D- 9T
E- T/9

1 answer:

svet-max [94.6K]3 years ago

5 0

Your answer is c sooooooooooo yea

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Why does the moon appear to wax grow larger and then wane or get smaller

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A fuse in an electric circuit is a wire that is designed to melt, and thereby open the circuit, if the current exceeds a predete

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Answer:

0.0389 cm

Explanation:

The current density in a conductive wire is given by

$J=\frac{I}{A}$

where

I is the current

A is the cross-sectional area of the wire

In this problem, we know that:

- The fuse melts when the current density reaches a value of

$J=520 A/cm^2$

- The maximum limit of the current in the wire must be

I = 0.62 A

Therefore, we can find the cross-sectional area that the wire should have:

$A=\frac{I}{J}=\frac{0.62}{520}=1.19\cdot 10^{-3} cm^2$

We know that the cross-sectional area can be written as

$A=\pi \frac{d^2}{4}$

where d is the diameter of the wire.

Re-arranging the equation, we find the diameter of the wire:

$d=\sqrt{\frac{4A}{\pi}}=\sqrt{\frac{4(1.19\cdot 10^{-3})}{\pi}}=0.0389 cm$

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