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monitta
3 years ago
12

A one-piece cylinder has a core section protruding from the larger drum and is free to rotate around its central axis. A rope wr

apped around the drum of radius 1.22 m exerts a force of 3.11 N to the right on the cylinder. A rope wrapped around the core of radius 0.62 m exerts a force of 6.92 N downward on the cylinder. 3.11 N 6.92 N What is the magnitude of the net torque acting on the cylinder about the rotation axis? Answer in units of N · m.
Physics
2 answers:
Rus_ich [418]3 years ago
7 0

Answer:

8.0846 N-m

Explanation:

The torques are in the same ( clockwise ) direction and so all we need to do is add the by calculating the torque and add

1.22×3.11 + 0.62×6.92 = 8.0846 N-m

magnitude of the net torque acting on the cylinder about the rotation axis

= 8.0846 N-m

11Alexandr11 [23.1K]3 years ago
6 0

Answer:

The net torque is 0.4962 N m

Explanation:

please look at the solution in the attached Word file

Download docx
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I have a question, it concerns hydrostatic buoyancy and Archimedes' law.
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3 years ago
The formation of condensation on a glass of ice water causes the ice to melt faster than it would otherwise. If 8.55 g of conden
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Answer:

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Explanation:

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so here we have

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now the energy of vaporization is given as

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here we know that

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8.55 \times 580 = m \times 79.8

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3 0
3 years ago
An open cart is rolling to the left on a horizontal surface. A package slides down a chute and lands in the cart. Which quantity
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Answer: the horizontal component of total momentum

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8 0
2 years ago
Solve this question
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Ok


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