That number has 6 significant numbers. It's precision would be 602.
Hope it helped.
The balanced nuclear equation for the reaction is
<h3>²³⁵₉₂U + ¹₀n —> ¹⁵⁵₆₂Sm + ⁷⁸₃₀Zn + 3(¹₀n)</h3>
From the question given above, we were told that:
<u>A fast-moving neutron strikes a ²³⁵U nucleus. The nucleus shatters producing ¹⁵⁵Sm, ⁷⁸Zn, and three neutrons.</u>
The nuclear equation can be written as follow:
Neutron => ¹₀n
Uranium => ²³⁵₉₂U
Samarium => ¹⁵⁵₆₂Sm
Zinc => ⁷⁸₃₀Zn
Uranium + neutron —> Samarium + Zinc + 3 moles of neutron
<h3>²³⁵₉₂U + ¹₀n —> ¹⁵⁵₆₂Sm + ⁷⁸₃₀Zn + 3(¹₀n)</h3>
The nuclear equation above is balanced.
Learn more: brainly.com/question/9943790
I believe it is the very first one
hope it helps :)
Answer : The oxygen will appears in the final chemical equation as a reactant.
Explanation :
The given chemical reactions are:
(1) 
(2) 
Now we are adding reaction 1 and reaction 2, we get the final chemical equation.
The final chemical equation is:
Thus, the oxygen will appears in the final chemical equation as a reactant.
C or D! When reduced coenzymes produce in the process of the cycle, are oxidized in the process of oxidative phosphorylation in electron transport chain! I hope this helps :(
