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GarryVolchara [31]
3 years ago
8

Light with a wavelength of 5.0 . 10-7 m strikes a surface that requires 2.0 ev to eject an electron. Calculate the frequency of

the glven wave.
1.5 x 102
6.0 x 1014
17 x 10-15
6.0 x 10-16​
Physics
1 answer:
andreyandreev [35.5K]3 years ago
4 0

Answer:

6.0\cdot 10^{14} Hz

Explanation:

The frequency and the wavelength of an electromagnetic wave are related by the wave equation:

c=f \lambda

where

c=3.0\cdot 10^8 m/s is the speed of light

f is the frequency

\lambda is the wavelength

For the light wave in this problem,

\lambda = 5.0\cdot 10^{-7} m is the wavelength

So, solving the equation for f, we find its frequency:

f=\frac{c}{\lambda}=\frac{3.0\cdot 10^8}{5.0\cdot 10^{-7}}=6.0\cdot 10^{14} Hz

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Metals in group 1 on the periodic table most commonly form which type of ion
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Answer:

Group 1 - the alkali metals. The Group 1 elements in the periodic table are known as the alkali metals.

Explanation:

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Scientists plan to release a space probe that will enter the atmosphere of a gaseous planet. The temperature of the gaseous plan
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D. 100 kilometers cuz the more kilometers the better the altitude!!!
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The current in a coil with a self-inductance of 1 mH is 2.8 A at t = 0, when the coil is shorted through a resistor. The total r
pogonyaev

Given:

L = 1 mH = 1\times 10^{-3} H

total Resistance, R = 11 \Omega

current at t = 0 s,

I_{o} = 2.8 A

Formula used:

I = I_{o}\times e^-{\frac{R}{L}t}

Solution:

Using the given formula:

current after t = 0.5 ms = 0.5\times 10^{-3} s

for the inductive circuit:

I = 2.8\times e^-{\frac{11}{1\times 10^{-3}}\times 0.5\times 10^{-3}}

I =   2.8\times e^-5.5

I =0.011 A

5 0
3 years ago
8. Three grams of Bismuth-218 decay to 0.375 grams in one hour. What is the half-
Evgen [1.6K]

Answer: 0.333 h

Explanation:

This problem can be solved using the <u>Radioactive Half Life Formula</u>:  

A=A_{o}.2^{\frac{-t}{H}} (1)  

Where:  

A=0.375 g is the final amount of the material  

A_{o}=3 g is the initial amount of the material  

t=1 h is the time elapsed  

H is the half life of the material (the quantity we are asked to find)  

Knowing this, let's substitute the values and find h from (1):

0.375 g=(3 g)2^{\frac{-1h}{H}} (2)  

\frac{0.375 g}{3 g}=2^{\frac{-1h}{H}} (3)  

Applying natural logarithm in both sides:

ln(\frac{0.375 g}{3 g})=ln(2^{\frac{-1 h}{H}}) (4)  

-2.079=-\frac{1 h}{H}ln(2) (5)  

Clearing H:

H=\frac{-1h}{-2.079}(0.693) (6)  

Finally:

h=0.333 h This is the half-life of the Bismuth-218 isotope

4 0
4 years ago
Sunitha can type 1800 words in half an hour. What is her typing speed in words per minute?
Andre45 [30]

Answer:

60words/minute

Explanation:

If Sunitha can type 1800 words in half an hour, this can be expressed as;

1800 words = 30 minutes

To get her typing speed per minute, we will use the formula

Speed = Number of words/Time used

Typing speed = 1800/30

Typing speed = 60words/minute

Hence her typing speed in words per minute is 60words/minute

6 0
3 years ago
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