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Levart [38]
3 years ago
11

Two cars collide head-on on a level friction-free road. The collision was completely inelastic and both cars quickly came to res

t during the collision. What is true about the velocity of this system's center of mass? Select one: a. It was never zero. b. It was always zero. c. It was not zero, but ended up zero. d. None of the above.
Physics
1 answer:
tangare [24]3 years ago
3 0

Answer:

b. It was always zero

Explanation:

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All of the following steps are included in a self-modification program except __________. A. specifying target behavior B. desig
Y_Kistochka [10]

Answer:

C)focusing on one goal at a time

Explanation:

Self-modification programs could be regarded as a program that help individual in managing unwanted as well as dysfunctional behavioral responses whenever they are going through a problem and try to deal with it. For instance the dysfunctional behavioral response for someone with a panic attack is avoidance. Some of the the steps that are involved in in a self-modification program are;

✓ specifying target behavior ✓designing a program

✓ gathering data about target behavior

8 0
3 years ago
Read 2 more answers
A worker pushes a crate horizontally across a warehouse floor with a force of 245 N at an angle of 55 degrees below the horizont
aev [14]

Answer:

option A

Explanation:

given,

For exerted by the worker = 245 N

angle made with horizontal = 55°

we need to calculate Force which is not used to move the crate = ?

Movement of crate is due to the horizontal component of the force.

Crate will not move due to vertical force acting on the it.

F_y = F sin \theta

F_y = 245\times sin 55^0

F_y =200.69

hence, worker's force not used to move the crate is equal to 200.69

The correct answer is option A

6 0
3 years ago
Read 2 more answers
A car is travelling at 18m/s accelerates ti 30m/s in 3seconds. what's the acceleration of the car​
Luden [163]

Answer: a = 4 m/s²

Explanation:

a = Δv/t = (30 - 18) / 3 = 4 m/s²

3 0
3 years ago
If it takes you 30 seconds to move a chair 20 meters across the floor, using a force of 5 Newton’s, how much power did you put o
natta225 [31]

Answer:

3.33 Joules Per Second

Explanation:

Before finding the Power, we need to calculate the Work Done. The Work Done can be calculated using the formula:

WD = F × d

where F is the Magnitude of Force in <em>N</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>d is the Parallel Distance moved by the object in <em>m</em><em>.</em>

Hence, by Applying this formula, we get:

WD = (5)(20)

= 100 J

From here calculating Power is simple as it is the Rate of Work Done. Hence,

Power = 100/30

= <u>3</u><u>.</u><u>3</u><u>3</u><u> </u><u>J</u><u>/</u><u>s</u>

Therefore, the power put out is <u>3</u><u>.</u><u>3</u><u>3</u><u> </u><u>J</u><u>o</u><u>u</u><u>l</u><u>e</u><u>s</u><u> </u><u>p</u><u>e</u><u>r</u><u> </u><u>S</u><u>e</u><u>c</u><u>o</u><u>n</u><u>d</u><u>.</u>

6 0
3 years ago
10 points
SOVA2 [1]

Explanation:

u=0 m/s

v=9.6 m/s

s= 40.5 m

a=?

V^2=u^2 +2as

9.6^2=0+2×a×40.5

92.16=81a

a=92.16/81

a=1.14m/s^2

3 0
3 years ago
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