A force of 5.0 N moves a 6.0 kg object along a rough floor at a constant speed of 2.5 m/s. (a) How much work is done in 25 s.

Physics

1 answer:

Pavel [41]3 years ago

6 0

Answer: ≈ 323 m

using Newton's 2nd law, we have:

F = ma

⇒ 5 = 6.a

⇔ a = 5/6 (m/s²)

the work done in 25s is $S=2,5.25+\frac{25^{2} }{2}.\frac{5}{6}$ ≈ 323 (m)

Explanation:

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