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kramer
3 years ago
12

If 1 gallon of a liquid weighs 4 pounds how much would one ounce weight (keep in mind that liquid ounces are different than weig

ht ounces)
Physics
1 answer:
Bas_tet [7]3 years ago
3 0

Answer:

64 ounces

Explanation:

Pound is the unit of mass in the imperial system of units.  It is used in the United States. Its calibration is done with the SI unit of mass which is kilogram. 1 lb =  0.45359237 kg

1 gallon = 4 pounds

1 pound = 16 ounces weight

So,

4 pounds = 16 × 4 = 64 ounces weight

So, 1 gallon is equal to 64 ounces weight.

1 gallon = 128 fluid ounces.

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An object moving with uniform acceleration has a velocity of 14.0 cm/s in the positive x-direction when its x-coordinate is 2.94
kotykmax [81]

Answer:

-19.9m/s²

Explanation:

Given that

vi = 14cm/s

xi = 2.94 cm

xf=-5.00 cm

t= 1.85s

So

Using xf-xi= vi t + 1/2at²

Which is = -5-2.94= 14*1.85+1/2a1.85²

= -7.94= 25.9+1.7a

-33.9= 1.7a

a= - 19.9m/s²

8 0
3 years ago
A cathode-ray tube (CRT) is an evacuated glass tube. Electrons are produced at one end, usually by the heating of a metal. After
Kobotan [32]

Answer: v = 5.79 * 10^10m/s.

Explanation: By using the work-energy theorem, we know that the work done on the electron by the potential difference equals the kinetic energy of the electrons.

Mathematically, we have that

qV = 1/2mv²

q= magnitude of an electronic charge = 1.609*10^-16c

V= potential difference = 95v

m = mass of an electronic charge = 9.11* 10^-31kg.

v = velocity of electron.

Let us substitute the parameters, we have that

1.609*10^-16 * 95 = (9.11*10^-31 * v²) /2

1.609*10^-16 * 95 * 2 = 9.11*10^-31 * v²

305.71 * 10^-16 = 9.11 * 10^-31 * v²

v² = 305.71 * 10^-16/ 9.11 * 10^-31

v² = 3.355 * 10^21.

v = √3.355 * 10^21

v = 5.79 * 10^10 m/s

5 0
3 years ago
A 0.14-km wide river flows with a uniform speed of 4.0 m/s toward the east. It takes 20 s for a boat to cross the river to a poi
Dmitry [639]

Answer:

The right approach is "8.1 m/s". A further explanation is provided below.

Explanation:

According to the table,

Speed of Boat

= \frac{s}{t}

V_b=\frac{140}{20}

V_a = 4 \ m/s

V_B = 7 \ m/s

Now,

⇒  (V_{relative})^2 = (7)^2+(4)^2

or,

⇒  (V_r)^2=49+16

              =65

         V_r=\sqrt{65}

              =8.1 \ m/s

7 0
2 years ago
What are some potential sources for error in conducting research?
harina [27]

Population specification errors occur when the researcher does not understand who they should survey. This can be tricky because there are multiple people who might consume the product, but only one who purchases it, or they may miss a segment looking to purchase in the future.

Population specification errors occur when the researcher does not understand who they should survey. This can be tricky because there are multiple people who might consume the product, but only one who purchases it, or they may miss a segment looking to purchase in the future.

Population specification errors occur when the researcher does not understand who they should survey. This can be tricky because there are multiple people who might consume the product, but only one who purchases it, or they may miss a segment looking to purchase in the future.

Population specification errors occur when the researcher does not understand who they should survey. This can be tricky because there are multiple people who might consume the product, but only one who purchases it, or they may miss a segment looking to purchase in the future.

Measurement error is generated by the measurement process itself, and represents the difference between the information generated and the information wanted by the researcher. Generally, there is always some small level of measurement error due to uncontrollable factors.

4 0
2 years ago
Read 2 more answers
A force of 20 N compresses a spring with a spring constant 50 N/m. How much energy is stored in the spring?
Alex787 [66]

Answer:

4J

Explanation:

Hooke's Law states:

F = -kx

where F = force

k = spring constant

x = displacement of spring

20 = -(50)x

-20/50 = x = -2/5

We can now use this information to find the energy in the Elastic Potential Energy Formula which is...

1/2(k)(x)^2

1/2(50)(2/5)^2 = 4J

3 0
3 years ago
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