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GaryK [48]
3 years ago
15

Stewart James, Calculus, Section 6.4, Page 449, Problem 5

Physics
1 answer:
faltersainse [42]3 years ago
4 0
The total work done is 
<span>W=60 plus 120
=180J

For the graphs please find the attached image</span>

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hooke's law is described mathematically using the formula fsp=-kx. which statement is correct about spring force, fsp? A. It is
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Answer:

A. It is always a positive force

Explanation:

Hooke's law describes the relation between an applied force and extension ability of an elastic material. The law states that provided the elastic limit, e, of a material is not exceeded, the force, F, applied is proportional to the extension, x, provided temperature is constant.

i.e F = - kx

where k is the constant of proportionality, and the minus sign implies that the force is a restoring force.

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3 years ago
An incompressible fluid flows steadily through a pipe that has a change in diameter. The fluid speed at a location where the pip
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Answer:

The value is v_2 =  5.53 \  m /s

Explanation:

From the question we are told

  The pipe diameter at location 1 is  d  = 8.8 \  cm =  \frac{8.8 }{10} = 0.88 \ m

   The velocity at location 1 is  v_1 =  2.4 \  m /s

   The diameter at location 2 is  d_2 =  5.80 \  cm  =  0.58 \  m

Generally the area at location 1 is  

       A_1 =  \pi *  \frac{d^2}{ 2}

=>     A_1 =  \pi *  \frac{0.88^2}{ 2}

=>     A_1 = 3.142 *  \frac{0.88^2}{ 2}

=>     A_1 = 1.2166 \  m^2

Generally the area at location 1 is  

       A_2 =  \pi *  \frac{d_1^2}{ 2}

=>     A_2 =  \pi *  \frac{0.58^2}{ 2}

=>     A_2 = 0.528  \  m^2

Generally from continuity equation we have that

     A_1 * v_1 =  A_2 * v_2

=>   1.2166 *   2.4   =  0.528   * v_2

=>   1.2166 *   2.4   =  0.528   * v_2

=>    v_2 =  5.53 \  m /s

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