Answer:
6.17 g/cm³
Explanation:
Data given:
one side of cube = 0.53 cm
mass of the cube is 0.92 g
density of the cube = ?
Solution:
First we will calculate for volume the cube
As we know all the sides or edges of a cube are equal so volume equation will be
So,
V = length x width x height
V = e³
as on side = 0.53 cm
then
V = (0.53 cm)³
V = 0.149 cm³
Now we will calculate density of cube
To calculate density, formula will be used
d = m/v . . . . . (1)
where
d = density
m = mass
v = volume
put values in above formula 1
d = 0.92 g / 0.149 cm³
d = 6.17 g/cm³
so. the density of cube = 6.17 g/cm³
Answer:
Zn =⇒ Zn+2(0.10) + 2e- (anode)
Zn+2(?M) + 2e- === Zn(s) (cathode)
Zn + Zn+2(?M) ===⇒ Zn+2(0.10) + Zn
E = E^o -0.0592 log Q; in this case E^o is zero.
E = - 0.0592 /n logQ where n is the number of electrons transferred, in this
case n = 2
23 mV x 1 volt/1000mv = 0.023 Volts
0.023 = -0.0592 / 2 log(0.10) / [Zn+2]
0.023 = -0.0296 { log 0.10 – log [Zn+2] }
0.023 = -0.0296{ -1 - log[Zn+2] }
0.023 = +0.0296 + 0.0296log[Zn+2]
-0.0066 = 0.0296log[Zn+2]
-0.22= log[Zn+2]
[Zn+2] = 10^-0.22 = 0.603 Molar
Answer:
B. Household ammonia.
Explanation:
NH₃ is a base, so the solution always will be basic.
NH₃ takes the proton from the water. In conclusion we have free OH⁻ in medium, that's why the solution is basic.
NH₃ + H₂O → NH₄⁺ + OH⁻
- HCl + H₂O → H₃O⁺ + Cl⁻
This reaction makes an acid solution, cause the H₃O⁺
- Vinegar is a compound made of acetic acid.
CH₃COOH + H₂O ⇄ H₃O⁺ + CH₃COO⁻
This reaction also makes an acid solution, cause the H₃O⁺
- Pure water makes neutral solution. It is not acid, neither basic.
2H₂O ⇄ H₃O⁺ + OH⁻
Things an animal does to survive are called behavioral adaptations. The correct option is c.
<h3>What is behavioral adaptation?</h3>
The adaptation of behavioral and physical characters that help to survive them.
For example, hibernating during winter, migration, etc. There are two types of behavioral adaptation, learned and instinctive.
Thus, the correct options are c: behavioral adaptations.
Learn more about behavioral adaptation
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the answer you have chosen is correct
