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Genrish500 [490]
3 years ago
13

The deepest portion of the lithosphere is formed from

Physics
1 answer:
aksik [14]3 years ago
3 0
It is formed from mantle material

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Which of these should you always do at the end of a calculation
yulyashka [42]

Answer:

Reverse check the answer

Explanation:

I believe it is very important that once someone is done with any calculation, the person ought to go over the calculations again. And even, recheck the answer in inverted form.

This is so because while doing the calculations, we can possibly make errors that we won't notice until after submission. Knowing 2 * 3 = 6, but writing 2 * 3 = 5 in the course of calculations can happen to anybody. So therefore, cross checking and reverse checking is needed

8 0
3 years ago
Which element has an isotope with 43 neutrons and a mass number of 76?
nexus9112 [7]

Answer:

B. Arsenic

Explanation:

76 - 43 = 33 protons

on a periodic table element 33 is Arsenic

7 0
3 years ago
A sphere of radius 5.15 cm and uniform surface charge density +12.1 µC/m2 exerts an electrostatic force of magnitude 35.9 ✕ 10-3
rosijanka [135]
The radius of the sphere is r=5.15 cm=0.0515 m, and its surface is given by
A=4 \pi r^2 = 4 \pi (0.0515 m)^2 = 0.033 m^2

So the total charge on the surface of the sphere is, using the charge density 
\rho=+1.21  \mu C/m^2 = +1.21 \cdot 10^{-6} C/m^2:
Q= \rho A = (+1.21 \cdot 10^{-6} C/m^2)(0.033 m^2)=4.03 \cdot 10^{-8}C

The electrostatic force between the sphere and the point charge is:
F=k_e  \frac{Qq}{r^2}
where
ke is the Coulomb's constant
Q is the charge on the sphere
q=+1.75 \muC = +1.75 \cdot 10^{-6}C is the point charge
r is their separation

Re-arranging the equation, we can find the separation between the sphere and the point charge:
r=\sqrt{ \frac{k_e Q q}{F} }= \sqrt{ \frac{(8.99 \cdot 10^9 Nm^2 C^{-2})(4.03 \cdot 10^{-8} C)(1.75 \cdot 10^{-6}C)}{35.9 \cdot 10^{-3}N} }=0.133 m=13.3 cm
8 0
3 years ago
Two cars are traveling around identical circular racetracks. Car A travels at a constant speed of 20 m/s. Car B starts at rest a
Tomtit [17]

Answer:

b. it has the same centripetal acceleration as car A.

Explanation:

According to the question, the data provided is as follows

Constant speed of car A = 20 m/s

Constant tangential acceleration until its speed is 40 m/s

Based on the above information, the true statement is the same centripetal acceleration as car A because

As we know that

Centripetal acceleration is

= \frac{V^2}{r}

where,

V^2 = velocity

r = radius of the path

Now if both car A and car B moving in the same or identical circular path having the same velocity so in this case there is the same centripetal acceleration for that particular time

hence, the second option is correct

3 0
4 years ago
0.0084x91 ...................
Drupady [299]

Answer:

0.0084×91=0.7644

Explanation:

hope this helps

8 0
3 years ago
Read 2 more answers
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