Reduction
half reaction
2H_2O
+ CrO_4^2- + 3e -> CrO_2^- + 4OH^-
Oxidation
half reaction
2OH^-
+ SO_3^2- -> SO_4^2- + H_2O + 2e
Balanced
overall equation
H_2O
+ 2CrO_4^2- + 3SO_3^2- -> 3SO_3^2- + 2CrO_2^- + 2OH^-
<span> </span>
Answer:
Brainliest pls
Explanation:
The components potassium and sodium have comparable substance properties since they have a similar number of valence electrons
<span>0.50 mg x ( 1 mL / 0.25 mg ) = 2 mL </span>
Answer:
52.5
Explanation:
how you get that is you divide be 3 to get the answer
HClO4 +NaOH -----> NaClO4 + H2O
moles of NaOH = (0.0832 x 50 ) /1000= 4.16 x10^-3 moles
since the mole ratio of HClO4 to NaOH is 1:1 the moles of HClO4 is also 4.16 x 10^-3 moles
volume of HClO4 is therefore = moles/ molarity
that is 4.16 x 10^-3mol/ 0.167 mol/L= 0.0249L
multiply by 1000 to convert to ml
0.0249 x 1000= 24.9 ml