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solmaris [256]
3 years ago
13

A stock phenolphthalein solution was prepared by dissolving 0.050 g in a total volume of 100.0 ml. You place one drop (0.050 ml)

of this stock solution into a flask and dilute to 100.0 ml. The measured absorbance of this diluted sample is 0.18. What is the value of molar absorptivity, ε?
Chemistry
1 answer:
devlian [24]3 years ago
3 0

Answer:

the value of molar absorptivity is 229000 M^{-1} cm^{-1}

Explanation:

given data

phenol phthalein solution = 0.050 g

total volume = 100.0 ml

dilute = 100.0 ml

diluted sample = 0.18

solution

we get here concentration that is express as

concentration = ( mass of solute × 1000 ) ÷ ( molar mass of solute × volume of solution ) .............1

put here value

concentration = \frac{0.050\times 1000}{318.32\times 100}    

concentration = 0.00157 M

and here dillution equation is express as

c1 × v1 = c2 × v2   .................2

here c1 and c2 is initial and final concentration

and v1 and v2 is initial and final volume

put here value  

0.001571 × 0.050 = c2 × 100

c2 = 7.855 × 10^{-7} M

and

now we get molar by absorbance equation that is

A = E × C ×  l   ................3

here A is absorbance and E is molar and c is absorptivity and l is path length

put here value

0.18 = E × 7.855 × 10^{-7}  × 1

E = 229000 M^{-1} cm^{-1}

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JulijaS [17]

1. The empirical formula of the hydrocarbon is CH₃

2. The molecular formula of the hydrocarbon is C₂H₆

<h3>How to determine the mass of Carbon </h3>
  • Mass of CO₂ = 1.47 g
  • Molar mass of CO₂ = 44 g/mol
  • Molar of C = 12 g/mol
  • Mass of C =?

Mass of C = (12 / 44) × 1.47

Mass of C = 0.4 g

<h3>How to determine the mass of H</h3>
  • Mass of compound = 0.5 g
  • Mass of C = 0.4 g
  • Mass of H = ?

Mass of H = (mass of compound) – (mass of C)

Mass of H = 0.5 – 0.4

Mass of H =0.1 g

<h3>1. How to determine the empirical formula </h3>
  • C = 0.4 g
  • H = 0.1 g
  • Empirical formula =?

Divide by their molar mass

C = 0.4 / 12 = 0.03

H = 0.1 / 1 = 0.1

Divide by the smallest

C = 0.03 / 0.03 = 1

H = 0.1 / 0.03 = 3

Thus, the empirical formula of the compound is CH₃

<h3>2. How to determine the molecular formula</h3>
  • Empirical formula = CH₃
  • Molar mass = 30 g/mol
  • Molecular formula =?

Molecular formula = empirical × n = mass number

[CH₃]n = 30

[12 + (3×1)]n = 30

15n = 30

Divide both side by 15

n = 30 / 15

n = 2

Molecular formula = [CH₃]n

Molecular formula = [CH₃]₂

Molecular formula = C₂H₆

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4 0
2 years ago
Does a bucket of water and an ice cube have the same chemical properties?
leva [86]
No, their specific heats are different. For water, and ice
3 0
3 years ago
Aniline, consists of carbon, hydrogen, and nitrogen. Combustion of this yields CO2, H20, and N2 as products. If the combustion o
ikadub [295]

The empirical formula : C. C₁₆H₁₅N₂

<h3>Further explanation</h3>

Given

12.5 g of aniline

7.1 grams of H2O

1.48 grams of N2

Required

The empirical formula

Solution

Reaction :

mass H in H₂O :

= 2.1/18 x 7.1 g

= 0.79

mass N = 1.48

mass C :

= 12.5 g-(mass H+mass N)

= 12.5 - (0.79+1.48)

= 10.23

Mol ratio C : H : N =

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= 0.853 : 0.79 : 0.106

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5 0
3 years ago
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A. physical change took place during the experiment. (plato users)

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