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slega [8]
3 years ago
11

hoose the best word or phrase to complete each sentence. 1.is a financial service that offers a kind of in the event of unforese

en damage, injury, or cost. 2.A is the cost of a type of insurance that is paid at regular intervals.
Chemistry
2 answers:
alex41 [277]3 years ago
8 0

Medical Insurance and Premium are the answers to your questions.

frosja888 [35]3 years ago
3 0

protection

Insurance

premium

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Identify the following reaction as oxidation and reduction F2(g)+2e-/2F-(aq)​
sertanlavr [38]

Answer:

Reduction

Explanation:

The oxidation reduction reactions are called redox reaction. These reactions are take place by gaining or losing the electrons and oxidation state of elements are changed.

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

In given reaction fluorine gas gain two electron and form fluoride ions.

F₂(g) + 2e⁻    →   2F⁻(aq)

The given reaction is reduction because oxidation state is decreased from zero to -1.

6 0
3 years ago
Noble gases will not bond with other atoms because of this reason?
Artyom0805 [142]
The valence electron ring is full. The ring has 8 electrons already.
5 0
3 years ago
Read 2 more answers
You have ice cubes in your freezer at home. The ice cubes melt into water. This type of change is called a... O a. nuclear chang
blagie [28]
B ) its a physical change
3 0
3 years ago
Which of the following has the strongest buffering capacity? A. H2O B. 0.1 M HCl C. 0.1 M carbonic/bicarbonate (H2CO3/HCO3-) at
enyata [817]

Explanation:

(A)   As we know that carbonic acid (H_{2}CO_{3}) and Sodium bicarbonate (NaHCO_{3}) forms an acidic buffer.

Therefore, pH of an acidic buffer is given by Hendeerson-Hasselbalch equation as follows.

               pH = pK_{a} + log(\frac{[Salt]}{[Acid]}) ........... (1)

So mathematically,  if [Salt] = [Acid]  then \frac{[Salt]}{[Acid]} = 1 .

And,  log (\frac{[Salt]}{[Acid]}) = 0

Therefore, equation (1) gives us the following.

         pH = pK_{a} (when acid and salt are equal in concentration)

Hence, pK_{a} of H_{2}CO_{3} (carbonic acid) is 6.35.

And, with this we have following results.

In (A) and (D) we have the case \frac{[NaHCO_{3}]}{[H_{2}CO_{3}]}[/tex] i.e. [Salt] = [Acid].

Hence, for the cases pH = pK_{a} = 6.35.

(B)    [NaHCO_{3}] = 0.045 M and,  [H_{2}CO_{3}] = 0.45 M

Hence,   pH = 6.35 + log([NaHCO_{3}][[H_{2}CO_{3}])

                     = 6.35 + log(\frac{0.045}{0.45})

                     = 6.35 + (-1)

                     = 5.35

Therefore, it means that this buffer will be most suitable buffer as it has pH on acidic side and addition of slight excess base will not affect much of its pH value.

(C)    [NaHCO_{3}] = 0.45 M [H_{2}CO_{3}]

                          = 0.045 M

So,       pH = 6.35 + log(\frac{[NaHCO_{3}]}{[H_{2}CO_{3}]})

                  = 6.35 + log(\frac{0.45}{0.045})

                  = 6.35 + (+1)

                 = 7.35

This means that pH on Basic side makes it no more acidic buffer.

5 0
3 years ago
An electrochemical cell has the following standard cell notation.
Alona [7]

Explanation:

The given following standard cell notation.  

Mg(s) | Mg^2+ (aq) || Aq^+(aq) | Aq(s)

Oxidation:

Mg(s)\rightarrow Mg^{2+}+2e^-....(1)

Magnesium metal by loosing 2 electrons is getting converted into magnesium cation. Hence, getting oxidized

Reduction:

Ag^+(aq)+1e^-\rightarrow Ag(s)...(2)

Silver ion by gaining 1 electrons is getting converted into silver metal. Hence, getting reduced.

Overall redox reaction: (1)+2 × (2)

Mg(s)+2Ag^+(aq)\rightarrow Mg^{2+}+2Ag(s)

4 0
3 years ago
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