Answer:
Nearly all of the hydrogen consumed in the United States is used by industry for refining petroleum, treating metals, producing fertilizer, and processing foods. U.S. petroleum refineries use hydrogen to lower the sulfur content of fuels.
Explanation:
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Answer:
13.4%
Explanation:
Take the molar mass (26.98) of Al x 2 because there are 2 moles in the given compound. Divide this number by the total molar mass of the compound (401.9) this gives you .134. To get a percentage mulitply by 100 for 13.4%.
[(26.98 x 2)/401.9] x 100 =13.4
Answer:
Defective collagen proteins affect an individuals joints, as <u>collagen is an important component protein in body</u><u> connective tissues</u>
Explanation:
Collagen is a crucial protein in the extracellular matrix of various connective tissues in body (tendons, ligaments, muscles). It constitutes major protein component in mammals body.
Collagen Vascular disease is a group of diseases affecting 'collagen' connecting tissue. Apart from inheritance, they can con occur due to autoimmune disease. This implies that body's immune system fights against itself & mistakenly damages its own tissues. So, these diseases have a huge bearing on body joints components. Eg : Lupus , Arthritis are common collagen vascular diseases. Arthritis mostly affects adults above 30 years of age, lupus can be diagnosed in younger people above 15 years of age also.
When mixture of NaCl and Al₂(SO₄)₃ is allowed to react with excess NaOH, only Al₂(SO₄)₃ reacts with it and NaCl does not react with NaOH due to presence of common ion (Na⁺). On reaction gelatinous precipitate of aluminium hydroxide [Al(OH)₃] is produced. The balanced chemical reaction is represented as-
Al₂(SO₄)₃ + 6NaOH → 2Al(OH)₃ + 3Na₂SO₄
On this reaction, 0.495 g = 0.495/78 moles =6.346 X 10⁻³ moles of Al(OH)₃.
As per balanced reaction, two moles of Al(OH)₃ is produced from one mole Al₂(SO₄)₃. So, 6.346 X 10⁻³ moles of Al(OH)₃ is produced from (6.346 X 10⁻³)/2 moles=3.173 X 10⁻³ moles of Al₂(SO₄)₃= 3.173 X 10⁻³ X 342 g of Al₂(SO₄)₃=1.085 g of Al₂(SO₄)₃.
So, mass percentage of Al₂(SO₄)₃ is= (amount of Al₂(SO₄)₃/total amount of mixture)X100 = =74.8 %.
Answer:
second box is 2 C, third box is 3 C, and the last box is 3 C.
Explanation: