The answer to your Question is E
To solve this problem we will apply the concepts related to load balancing. We will begin by defining what charges are acting inside and which charges are placed outside.
PART A)
The charge of the conducting shell is distributed only on its external surface. The point charge induces a negative charge on the inner surface of the conducting shell:
. This is the total charge on the inner surface of the conducting shell.
PART B)
The positive charge (of the same value) on the external surface of the conducting shell is:
![Q_{ext}=+Q_1=1.9*10^{-6} C](https://tex.z-dn.net/?f=Q_%7Bext%7D%3D%2BQ_1%3D1.9%2A10%5E%7B-6%7D%20C)
The driver's net load is distributed through its outer surface. When inducing the new load, the total external load will be given by,
![Q_{ext, Total}=Q_2+Q_{ext}](https://tex.z-dn.net/?f=Q_%7Bext%2C%20Total%7D%3DQ_2%2BQ_%7Bext%7D)
![Q_{ext, Total}=1.9+3.8](https://tex.z-dn.net/?f=Q_%7Bext%2C%20Total%7D%3D1.9%2B3.8)
![Q_{ext, Total}=5.7 \mu C](https://tex.z-dn.net/?f=Q_%7Bext%2C%20Total%7D%3D5.7%20%5Cmu%20C)
Answer:
Mass and distance
Explanation:
According to Newton’s law, “objects with greater mass have a stronger force of gravity between them.” And “objects that are closer together have a stronger force of gravity between them.” Both of them mean mass and distance. Therefore, the correct answer is mass and distance.
Answer:
v ’= - 1.76 10⁻⁴ m / s
Explanation:
We can solve this problem using momentum conservation. Defined a system formed by the patient, his blood and the platform in such a way that the forces are internal and the moment is conserved
initial instnate. Before pumping
p₀ = 0
final instant. Right after the heart pumping
p_f = m v + M v'
where m is the mass of blood and M the mass of the patient + the platform
p₀ = p_f
0 = m v + M v’
v ’= - ![\frac{m}{M} \ v](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7BM%7D%20%5C%20v)
let's calculate
v ’= -
0.30
v ’= - 1.76 10⁻⁴ m / s